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Oksi-84 [34.3K]
3 years ago
11

The inventory data for an item for November are:a. Nov. 1: Inventory 20 units at $19b. Nov. 10: Purchased 30 units at $20c. Nov.

4: Sold 10 unitsd. Nov. 17: Sold 20 unitse. Nov. 30: Purchased 10 units at $21Using a perpetual system, what is the cost of the merchandise sold for November if the company uses LIFO?a. $610b. $600c. $590d. $580
Business
2 answers:
spin [16.1K]3 years ago
6 0

Answer:

c.$590

Explanation:

The LIFO system is one in which items are last purchased are sold first. this may not be the best system of inventory valuation for items with expiry dates.

Given that the company sold 10 and 20 units on Nov 4 and Nov 17

The sale on Nov 4 would have been the items purchased on Nov 1 while the sale on Nov 17 must have been from the purchase made on Nov 10

Hence Inventory sold cost

= $19 * 10 + $20 *20

= $590

Zigmanuir [339]3 years ago
4 0

Answer:

the cost of the merchandise sold for November if the company uses LIFO is c. $590

Explanation:

LIFO Inventory System sells the Inventory recently acquired first followed by the Older Inventory Acquired.

<u>Cost of the merchandise sold for November - Calculation</u>

November 4 : 10 units × $19    =$190

November 17 : 20 units × $20 =$400

Total                                          =$590

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Answer and Explanation:

The computation of the service level and the corresponding optimal stocking level is shown below:

Given that

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Average daily demand (d) = 35 quarts

The  standard deviation of daily demand  = 4 quarts

based on the above information

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Now

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= $4.50 - $3.00

= $1.50

So,  

Service level is

= Cu ÷ (Co + Cu)

= 1.50 ÷ (1.50 + 1.50)

= 1.50 ÷ 3.00

= 0.50

= 50%

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= 35 + (0  × 4)

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Read 2 more answers
Sheffield Laboratories holds a valuable patent (No. 758-6002-1A) on a precipitator that prevents certain types of air pollution.
vlabodo [156]

Answer:

                        SHEFFIELD LABORATORY

                            PATENT (NO. 78-6002-1A)

Carrying value as at Dec 31

                                      2011                     2015                   2018

Cost                            $182,300           $349,000           $385,000

Amortization             <u> (10,724)   </u>             <u>(79,433)  </u>           <u>(142,403)</u>

                                 <u> 171,576     </u>         <u>   269,567  </u>           <u>242,597</u>

Cost

As at 31 Dec 2011

Design and construction of a prototype                                     $89,000

Testing of models                                                                           40,600

Fees paid engineers and lawyers to prepare application          <u> 52,700</u>

                                                                                                       <u>$182,300</u>

As at 31 Dec 2012

Cost as at Jan 1, 2012                                                                $182,300

Additional cost during the year:

Engineering activity necessary to advance.                           <u> $84,500  </u>

                                                                                                    <u>$266,800</u>

As at 31 Dec 2013

Cost as at Jan 1, 2013                                                                $266,800

Additional cost during the year:

legal fee paid                                                                              <u>$40600  </u>

                                                                                                 <u>   $307,400</u>

As at 31 Dec 2014

Cost as at Jan 1, 2013                                                                $307,400

Additional cost during the year:

Research aimed at modifying the design                                <u>$41,600 </u>

                                                                                                   <u> $349,000</u>

As at 31 Dec 2018

Cost as at Jan 1, 2018                                                                $349,000

Additional cost during the year:

legal fee paid in unseccesful patent infrigement.                   <u>  $36,000  </u>

                                                                                                    <u>$385,000</u>

Amortization for the year    

Dec 31 2011         $182,300/17 =  $10,724

Dec 31 2012

182,300/17                                          10,724

84,500/0                                          <u>      -       </u>

                                                         <u>  10,724</u>

<u />

Dec 31 , 2013 :

  $182,300/17 =  $10,724            

  84,500/16    =      5,281

40,600/0     =     <u>    -  </u>

                         <u>   16,005</u>

Dec 31 2014  =  

$182,300/17 =  $10,724            

  84,500/16    =      5,281

40,600/16     =       2,538

41,600/17      =       <u> 2,447</u>

                         <u>   20,990</u>

Dec 31 2018  =  

$182,300/17 =  $10,724            

  84,500/16    =      5,281

40,600/16     =       2,538

41,600/17      =        2,447

36,000/0     =    <u>       -</u>

                         <u>   20,990</u>

Explanation:

5 0
4 years ago
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