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Elis [28]
3 years ago
6

An engineer is making adjustments on a satellite, because he finds it is not focusing the incoming radio waves perfectly. The sh

ape of his satellite can be modeled by the equation (y − 3)2 = 2(x − 2), where x and y are measured in inches. He realizes the static is a result of the feed antenna shifting lightly off the focus point. How many inches in front of the vertex should the feed antenna be?
Mathematics
1 answer:
vodomira [7]3 years ago
7 0

Answer:

The answer is 1/2 inches

Step-by-step explanation:

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If \triangle ABC△ABC is equilateral, solve for x. <br><br><br><br><br> x=
Gwar [14]

Answer:

x = 13

Step-by-step explanation:

The tirangle ABC is given as equilateral. Every angle is therefore =. Not only that, each angle is 60 degrees.

If you need proof of that, remember that x + x + x  = 180. Every triangle has 180 degrees.

if 3x = 180 then 1 x is 60

8x - 44 = 60       Add 44 to both sides.

8x = 60 + 44

8x = 104             Divide by 8

x = 104/8

x = 13

6 0
3 years ago
Read 2 more answers
What is the range of y = sinx in the interval - π ≤ x ≤ 0?
Kaylis [27]

Answer:

-1 \le y \le 1

Step-by-step explanation:

Let be y = \sin x, the range of the function corresponds to the set of values of y. The sine function is a bounded function between -1 and 1. Hence, the range of the function is:

-1 \le y \le 1

6 0
3 years ago
Lol I NEED HELP!!!! and if you write something thats not the answer then ill REPORT you
Ilya [14]
A) an equal chance or 50-50
There is the same amount of each flavor so it has an equal chance of being cherry or strawberry.
6 0
3 years ago
Find the complex fourth roots \[-\sqrt{3}+\iota \] in polar form.
____ [38]

Let z=-\sqrt3+i. Then

|z|=\sqrt{(-\sqrt3)^2+1^2}=2

z lies in the second quadrant, so

\arg z=\pi+\tan^{-1}\left(-\dfrac1{\sqrt3}\right)=\dfrac{5\pi}6

So we have

z=2e^{i5\pi/6}

and the fourth roots of z are

2^{1/4}e^{i(5\pi/6+k\pi)/4}

where k\in\{0,1,2,3\}. In particular, they are

2^{1/4}e^{i(5\pi/6)/4}=2^{1/4}e^{i5\pi/24}

2^{1/4}e^{i(5\pi/6+2\pi)/4}=2^{1/4}e^{i17\pi/24}

2^{1/4}e^{i(5\pi/6+4\pi)/4}=2^{1/4}e^{i29\pi/24}

2^{1/4}e^{i(5\pi/6+6\pi)/4}=2^{1/4}e^{i41\pi/24}

7 0
3 years ago
25 out of 27 as a percentage
Basile [38]
25/27 = 0.925925925...

It's almost equal to 1 and it turns out that 1 is 100%.

So, we'd say that it's equal to:

92.59% (to 2 decimal places)

We've multiplied the value above (25/27) by 100.
8 0
3 years ago
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