5 is the answer to your question.
Answer:
The 95% confidence interval estimate of the true population proportion of U.S. employers that were likely to require higher employee contributions for health care coverage is 0.52 +/- 0.0370
= (0.4830, 0.5570)
The margin of error M.E = 0.0370
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
p+/-z√(p(1-p)/n)
p+/-M.E
Given that;
M.E = margin of error
Proportion p = 52% = 0.52
Number of samples n = 700
Confidence interval = 95%
z value (at 95% confidence) = 1.96
Substituting the values we have;
0.52 +/- 1.96√(0.52(1-0.52)/700)
0.52 +/- 1.96(0.0189)
0.52 +/- 0.0370
( 0.4830, 0.5570)
The 95% confidence interval estimate of the true population proportion of U.S. employers that were likely to require higher employee contributions for health care coverage is 0.52 +/- 0.0370
= (0.4830, 0.5570)
The margin of error M.E = 0.0370
Every fraction is just a short way to write a division.
Whenever you see a fraction, it means
the top number
divided by
the bottom number.
When you actually do the division, like with a pencil or a calculator,
the quotient you get is the decimal form of the fraction.
I won't insult your intelligence by giving you 7 divided by 25 .
I'm sure you can do that easily.
I also won't insult your intelligence by sending you to a web site.
I assume that if you were on a desert island without your phone
or any 4G coverage, you'd be able to figure out a way to divide
7 by 25.
The answer for this is the rules is x n y
