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Tresset [83]
3 years ago
15

Identify an equation in point-slope form for the line perpendicular to

Mathematics
1 answer:
Alchen [17]3 years ago
3 0

Answer:

y - 9 = \frac{1}{2}(x +3)

Step-by-step explanation:

Given

Function; y = -2x + 8

Required

Find an equation perpendicular to the given function if it passes through (-3,9)

First, we need to determine the slope of:  y = -2x + 8

The slope intercept of an equation is in form;

y = mx + b

<em>Where m represent the slope</em>

Comparing  y = m_1x + b to y = -2x + 8;

We'll have that

m_1 = -2

Going from there; we need to calculate the slope of the parallel line

The condition for parallel line is;

m_1 * m_2 = -1

Substitute m_1 = -2

(-2) * m_2 = -1

Divide both sides by -2

m_2 =\frac{ -1}{-2}

m_2 =\frac{1}{2}

The point slope form of a line is;

y - y_1 = m_2(x - x_1)

Where (x_1,y_1) = (-3,9) and m_2 =\frac{1}{2}

y - y_1 = m_2(x - x_1)becomes

y - 9 = \frac{1}{2}(x - (-3))

Open the inner bracket

y - 9 = \frac{1}{2}(x +3)

<em>Hence, the point slope form of the perpendicular line is: </em>

<em />y - 9 = \frac{1}{2}(x +3)<em />

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Find the length of the segment AB if points A and B are the intersection points of the parabolas with equations y=−x^2+9 and y=2
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Answer:

The length of the segment AB is √48

Step-by-step explanation:

Given the two equations, the idea is to find the solution to the system

y = x² + 9

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x² + 9 = 2x² - 3 ⇒ x² - 2x² = -3 - 9 ⇒ -x² = -12 ⇒ x² = 12 ⇒ x = ±√12.

With this value we return to the original equations and replace it to find "y" values.

y = (±√12)² + 9 ⇒ y = 21

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d= √[(x2-x1)² + (y2-y1)²] ⇒ d = √48.

The length of the segment AB is √48.

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