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Wewaii [24]
3 years ago
6

For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 21 N acts on

a certain object, the acceleration of the object is 7 m/s^2 . If the acceleration of the object becomes 10 m/s^2 , what is the force?
Mathematics
1 answer:
Marat540 [252]3 years ago
4 0

Answer:

21N:7m/s

? :10m/s

21x10=210

210÷7=30N

Your final answer is 30N

Step-by-step explanation:

This is called direct propotion

it involves close multiplication

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9) -9x - 13 - y = 0<br> 7=-y-3x
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Answer:

The value of x and y  is ,

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Step-by-step explanation:

The given two linear equation can be written as ,

y + 9x = -13            ....1     and

y - 3x = 7              .....2

Put the value of y from eq 1 into eq 2

i.e (-13 -9x) - 3x = 7

or, -12x = 7 +13

Or, -12x = 20

i.e X = \frac{-5}{3}

Now put t his value of x in any above two linear equation

Let put this value on eq 2 to get value of y

so its can be writen as.

y = 3x + 7

or, y = 3(\frac{-5}{3}) + 7

or, y = -5 +7

i.e Y = 2

Hence the value of x and y  is , x = \frac{-5}{3}  and y = 2  Answer

6 0
3 years ago
What information does the ordered pair (3, 87) represent?
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