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Marizza181 [45]
3 years ago
9

What is the volume of the sphere below?

Mathematics
1 answer:
Mamont248 [21]3 years ago
7 0

Answer:

ans is (D)500/3 π unit^3

Explanation :

Formula for volume of sphere is 4/3 π r^3 .

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A 13 ft ladder is resting on a wall. The angle the ladder makes with the floor is 45 degrees. How high off the ground is the top
PtichkaEL [24]

Answer: 9.19 ft

Step-by-step explanation:

Hi, since the situation forms a right triangle (see attachment) we have to apply the next trigonometric function.  

Sin α = opposite side / hypotenuse  

Where α is the angle of elevation of the ladder to the ground, the hypotenuse is the longest side of the triangle (in this case is the length of the ladder), and the opposite side (x) is distance between the top of the ladder and the ground.

Replacing with the values given:  

Sin 45 = x/ 13

Solving for x  

sin45 (13) =x  

x= 9.19 ft

Feel free to ask for more if needed or if you did not understand something.  

6 0
3 years ago
Simplify<br> 21^6y^5/14x^2y^9
nevsk [136]

1 2 2 5 2 3 0 3 ^1 4 ^2/2

6 0
2 years ago
The average person laughs 15 times per day.
drek231 [11]
Really? i didn’t know.
7 0
3 years ago
Read 2 more answers
A data set includes 103 body temperatures of healthy adult humans having a mean of 98.3degreesF and a standard deviation of 0.73
faust18 [17]

Answer:

CI = (98.11 , 98.49)

The value of 98.6°F suggests that this is significantly higher

Step-by-step explanation:

Data provided in the question:

sample size, n = 103

Mean temperature, μ = 98.3

°

Standard deviation, σ = 0.73

Degrees of freedom, df = n - 1 = 102

Now,

For Confidence level of 99%, and df = 102, the t-value = 2.62      [from the standard t table]

Therefore,

CI = (Mean - \frac{t\times\sigma}{\sqrt{n}},Mean + \frac{t\times\sigma}{\sqrt{n}})

Thus,

Lower limit of CI =  (Mean - \frac{t\times\sigma}{\sqrt{n}})

or

Lower limit of CI =  (98.3 - \frac{2.62\times0.73}{\sqrt{103}})

or

Lower limit of CI = 98.11

and,

Upper limit of CI =  (Mean + \frac{t\times\sigma}{\sqrt{n}})

or

Upper limit of CI =  (98.3 + \frac{2.62\times0.73}{\sqrt{103}})

or

Upper limit of CI = 98.49

Hence,

CI = (98.11 , 98.49)

The value of 98.6°F suggests that this is significantly higher and  the mean temperature could very possibly be 98.6°F

7 0
3 years ago
The average (arithmetic mean) of y numbers is x. If 30 is added to the set of numbers, then the average will be x − 5. What is t
Alenkasestr [34]

Answer:

y = \frac{1}{5}(x^{2}-35x)

Step-by-step explanation:

Let the total numbers are n.

If the average of y numbers is x then we can form an equation

\frac{y}{n}=x

⇒ \frac{n}{y}=\frac{1}{x}

⇒ n = \frac{y}{x} --------(1)

Now 30 is added to the set of numbers then average becomes (x - 5)

\frac{y+30}{n+1}=(x-5)

⇒ \frac{(n+1)}{(y+30)}=\frac{1}{(x-5)}

⇒ (n + 1) = \frac{y+30}{x-5}

⇒ n = \frac{y+30}{x-5} - 1 ----- (2)

Now we equate the values of n from equation 1 and 2

\frac{y}{x} = \frac{y+30}{x-5} - 1

y(x - 5) = x(y + 30) - x(x - 5)  [ By cross multiplication ]

xy - 5y = xy + 30x - x² + 5x

xy - xy - 5y = 35x - x²

-5y = 35x - x²

x² - 35x = 5y

y = \frac{1}{5}(x^{2}-35x)

6 0
3 years ago
Read 2 more answers
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