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maks197457 [2]
3 years ago
15

What is the solution, if any, to the inequality |3x|>_0?|

Mathematics
2 answers:
WINSTONCH [101]3 years ago
3 0

Answer:

x\geq0

Step-by-step explanation:

if you plug it into symbolab, it tells you that absolute values are greater to or equal to 0, and that it's always true.

Cloud [144]3 years ago
3 0

Answer:

all real numbers

Step-by-step explanation:

photomath

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I need help fast……….
kap26 [50]

Answer:

all real numbers

the domain of any parabola is all real numbers because it gets wider.

8 0
2 years ago
You are taking an exam and there are still many questions left to be solved. You already got 18 questions correct out of 25. The
UkoKoshka [18]

The answer is 2

Step-by-step explanation: 100% is the highest score you can have  . then you have to divide 25 by 100 because 25 is the total amount of questions ,you should get 4,wich means each question is worth 4 points.

18 correct is a score of 72

20 correct is a score of 80

4x2=8 wich you need 8 more to get to 80 from 72

feel free to ask for more help :)

8 0
4 years ago
An olympic-size swimming pool is a rectangle that measures 50 meters in length and 25 meters in width. Make a scale drawing of a
Veronika [31]

Answer:

Length: 10 cm

Width: 5 cm

Step-by-step explanation:

8 0
3 years ago
What are the coordinates of the point on the directed line segment from (6, -10) to
sveta [45]

Answer:

There are 2

(6 2/5, -6 2/5)

(8 3/5, 4 2/5)

Step-by-step explanation:

8 0
3 years ago
If a = pi +3j - 7k, b = pi - pj +4k and the angle between a and is acute then the possible values for p are given by​
PIT_PIT [208]

Answer:

The family of possible values for p are:

(-\infty, -4) \,\cup \,(7, +\infty)

Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|} (1)

Where:

\theta - Angle between vectors, in sexagesimal degrees.

\|\vec a\|, \|\vec b \| - Norms of vectors \vec {a} and \vec{b}

If \theta is acute, then the cosine function is bounded between 0 a 1 and if we know that \vec {a} = (p, 3, -7) and \vec {b} = (p, -p, 4), then the possible values for p are:

Minimum (\cos \theta = 0)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} > 0

Maximum (\cos \theta = 1)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} < 1

With the help of a graphing tool we get the family of possible values for p are:

(-\infty, -4) \,\cup \,(7, +\infty)

7 0
3 years ago
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