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jarptica [38.1K]
3 years ago
6

Rhombus WXYZ with vertices W(1,5), X(6, 3), Y(1, 1), and Z(-4, 3) in the x-axis.

Mathematics
1 answer:
vlada-n [284]3 years ago
4 0

9514 1404 393

Answer:

  W'(1,-5), X'(6,-3), Y'(1,-1), Z'(-4,-3)

Step-by-step explanation:

Reflection over the x-axis changes the sign of the y-coordinate. The x-coordinate remains unchanged.

The reflected points are ...

  W'(1,-5), X'(6,-3), Y'(1,-1), Z'(-4,-3)

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He should charge 16.25 for each pack
6 0
3 years ago
What is the general form of the quadratic with vertex at (2, 3) and passing through the point (5, 12)?
ki77a [65]

The general form of the quadratic with vertex at (2, 3) and passing through the point (5, 12) is x²-4x+7.

<h3>What is the vertex form of a quadratic equation?</h3>

Vertex form of the quadratic equation is used to find the coordinate of vertex points at which it crosses its symmetry.

The standard equation of the vertex form of quadratic is given as,

y=a(x-h)^2+k

Here, (h, k) is the vertex point.

The vertex of quadratic at (2, 3) and passing through the point (5, 12). Put the value of vertex point in the above equation,

y=a(x-2)^2+3

As the quadratic passes through the point (5, 12). Thus, put the value of this point,

12=a(5-2)^2+3\\12-3=a(3)^2\\9=a\times9\\a=\dfrac{9}{9}\\a=1

Put the value of <em>a</em> in the above expression,

y=1(x-2)^2+3\\y=(x-2)^2+3\\y=x^2-4x+4+3\\y=x^2-4x+7

Thus, the general form of the quadratic with vertex at (2, 3) and passing through the point (5, 12) is x²-4x+7.

Learn more about the vertex form here;

brainly.com/question/17987697

#SPJ1

4 0
3 years ago
Question is attached, Don't worry explaining too much just make sure the answer is correct :))
garik1379 [7]

Answer:

The image below will explain the question

To figure out the length of portion BC, we will use the trigonometric ratio below

\begin{gathered} \sin\theta=\frac{opposite}{hypotenus} \\ oppsite=BC \\ hypotenus=8in \\ \theta=35 \end{gathered}

By substituting the values, we will have

\begin{gathered} \sin(\theta)=\frac{oppos\imaginaryI te}{hypotenus} \\ \sin35=\frac{BC}{8} \\ cross\text{ multiply, we will have} \\ BC=8\sin35 \end{gathered}

Hence,

The final answer is

\Rightarrow8\sin35^0

The FOURTH OPTION is the right answer

8 0
1 year ago
The number of polynomials having zeros as -2 and 5 is a)1 b)2 c)3 d)more than 3
WINSTONCH [101]

Answer:

d) More than 3.

Step-by-step explanation:

The polynomial (x - 5)(x + 2)  ( = x^2  - 3x + 10) has zeros of -2 and 5 but so have the polynomials formed by multiplying this by any integer:

- for example 2(x - 5)(x + 2) , 4(x - 5)(x + 2) and so on.

3 0
3 years ago
Please help me i dont know how to do the down part.
torisob [31]

Answer:

40, 60, 80, 100, 120, 140, 160, 180, 200

Step-by-step explanation:as the 12 goes up by 12 the 20 goes up by 20

8 0
3 years ago
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