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2 years ago

Rhombus WXYZ with vertices W(1,5), X(6, 3), Y(1, 1), and Z(-4, 3) in the x-axis.

Mathematics

1 answer:

vlada-n [284]2 years ago

4 0

9514 1404 393

Answer:

W'(1,-5), X'(6,-3), Y'(1,-1), Z'(-4,-3)

Step-by-step explanation:

Reflection over the x-axis changes the sign of the y-coordinate. The x-coordinate remains unchanged.

The reflected points are ...

W'(1,-5), X'(6,-3), Y'(1,-1), Z'(-4,-3)

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A. 3<br> B. -3/4<br> C. -1<br> D. 2

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B
because rise over run

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3 years ago

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Lola rode her bike for 7/10 of an hour on saturday and 3an hour on sunday.how much longer did she ride her bike on saturday than

Artyom0805 [142]

She rode 2 and 3/10 more hours

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2 years ago

Show both decimal places (5.06).

lilavasa [31]

a. the cost of a call for six minutes is 0.70.

b.the cost of a 14-minute call is 2.62.

c.the cost of a 9 ½2-minute call is 1.66.

given that

rate schedule for an m-minute call from any of its pay phones 0.70.

c(m) = 0.70 when m<=6

c(m) = 0.70+ 0.24(m-6) when m>6 & m is an integer

c(m) = 0.70+0.24((m-6)+1) when m>6 & m is not an integer.

a. to find the cost of a call for six minutes.

already given that c(m) =0.70 when m=6.

Therefore, the cost of a call for six minutes is 0.70.

b. to find the cost of a 14-minute call.

according to given information

$c(14) = 0.70 + 0.24(m - 6) \\ c(14) = 0.70 + 0.24(14 \: - 6) \\c(14) = 0.70 + (0.24 \times 14) - (0.24 \times 6) \\c(14) = 0.70 + (3.36 - 1.44) \\ c(14) = 0.70 + 1.92 \\ c(14) = 2.62$

Therefore,the cost of a 14-minute call is 2.62.

c.to find the cost of a 9 ½2-minute call

according to given information

$c(9 \frac{1}{2} 2) = 0.70 + 0.24((9 \frac{1}{2} 2 - 6) + 1) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.24((9 - 6) + 1) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.24(3+ 1) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.24(4) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.96 \\ c(9 \frac{1}{2} 2) = 1.66$

Therefore,the cost of a 9 ½2-minute call is 1.66.

Learn more about problems on cost of call, refer:

brainly.com/question/16584226

#SPJ9

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1 year ago

1) g=-y+c/x, solve for X

Sindrei [870]

Answer:

the solution $x = \frac{c}{g-y}$

Step-by-step explanation:

Given problem $g=\frac{-y+c}{x}$

here l.cm is x

$g = \frac{x y+c}{x}$

cross multiplication we get ,

$g x = x y +c$

<u>Step 2</u>:-

subtracting x y on both sides , we get

$g x - x y = c$

taking common 'x' we get,

$x(g-y) = c$

<u>Final answer</u>:-

$x = \frac{c}{g-y}$

3 0

3 years ago

20 how much metal is needed to smelt a cubical metal box with outer side 12 inches long if the thickness of its walls should be

guajiro [1.7K]

The volume of the metal box if the box was completely solid (V1), is:

V1=(12 inches)³
V1=1728 inches³

As there are 3 inches of metal on both sides, the widht if the metal box was not completely solid, is:

W=12 inches-(3 inchesx2)
W=6 inches

Then, the volumen of the no solid metal box is:

V2=(6 inches)³
V2= 216 inches³

Therefore, the volume of metal needed to smelt the cubical metal box, is:

V3=V1-V2
V3=1728 inches³-216 inches³
V3=1512 inches³

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3 years ago