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Marat540 [252]
3 years ago
15

PLS HELP!!!!! WILL GIVE BRAINLIEST, 5 STARS, AND THANKS!!!!!!!!!!

Chemistry
2 answers:
Basile [38]3 years ago
8 0
The value that n must be in the organic compound is that it must be 5. This will result in the name of the hydrocarbon to be heptane as heptane possess 7 carbons in the longest parent chain. So the formula would be CH3(CH2)5CH3. Distributing the 5 inside and making it a subscript to the carbon gives us 5. Adding up all of the carbons together should give you the correct number of carbon atoms with respect to its name, heptane. 1+5+1= 7. so the answer is 5
lana [24]3 years ago
6 0

Answer:

n=5

Explanation:

Hydrocarbons are named according to the number of carbons they possess in their structure.

So, write the structure given by the problem:

CH_{3}(CH_{2})_{n}CH_{3}

Then take in account that the prefix "hepta" indicates that the compound has 7 carbons in its structure and the ending "ane" indicates that it is an alkane, that is, it has only simple bonds between the carbon molecules in its structure.  Also each carbon can form 4 simple bonds, either with a carbon atom or with a hydrogen atom.

Therefore n=5, and the structure will be:

CH_{3}(CH_{2})_{5}CH_{3}

That is five times the CH_{2}. Or written in other way:

CH_{3}-CH_{2}-CH_{2}-CH_{2}-CH_{2}-CH_{2}-CH_{3}

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Answer:

pretty sure it's C,

Explanation:

Mantle convection is the very slow creeping motion of Earth's solid silicate mantle caused by convection currents carrying heat from the interior to the planet's surface. ... This hot added material cools down by conduction and convection of heat.

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To cook a steak to medium-rare, it needs to have an internal temperature of 135
Nady [450]

t<135 because it will be less then 135°

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So3+H2o→H2 So4<br>identify the nature of this reaction<br>helpp please i'm such a failure​
Harrizon [31]

THE REACTION IS COMBINATION REACTION!

6 0
3 years ago
Find the energy in kJ for an x-ray photon with a frequency of 2.4 × 10^18 1/s.
Ilya [14]

Answer:

15912 × 10∧-19 KJ

Explanation:

Given data;

frequency of photon = 2.4 × 10^18 1/s.

Planck's constant = 6.63 × 10∧-34 j.s

Energy = ?

Formula:

E = h × ν

E =  6.63 × 10∧-34 j.s ×  2.4 × 10^18 1/s

E= 15.912 × 10∧-16 j

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8 0
3 years ago
A volume of 100 mL of 1.00 M HCl solution is titrated with 1.00 M NaOH solution. You added the following quantities of 1.00 M Na
s344n2d4d5 [400]

Answer:

a: before equivalence point

b: equivalence point

c: before equivalence point

d: after the eqivalence point

e: before equivalence point

f:  after the eqivalence point

Explanation:

Balanced equation of reaction:

NaOH +HCl =NaCl +H2O;

Volume of HCl is fixed and it 100ml and concentration is 1.0M

N1 and N2 normality of HCl and NaOH respectively;

V1 and V2 volume of HCl and NaOH respectively;

we have given molarity but we need normality;

Normality=molarity \times n-factor

<em>but in case of NaOH and HCl n-factor is 1 for each.</em>

hence

normality=molarity;

At equivalence point:  N_1V_1=N_2V_2

Before equivalence point : N_1V_1>N_2V_2

After the equivalence point: N_1V_1

N_1V_1=100\times1=100

case a:  5.00 mL of 1.00 M NaOH

N_2V_2=5\times1=5

N_1V_1>N_2V_2 hence it is before equivalence point

case b: 100mL of 1.00 M NaOH

N_2V_2=100\times1=100

N_1V_1=N_2V_2 hence it is equivalence point

case c:  10.0 mL of 1.00 M NaOH

N_2V_2=10\times1=10

N_1V_1>N_2V_2 hence it is before equivalence point

case d: 150 mL of 1.00 M NaOH

N_2V_2=150\times1=150

N_1V_1 hence it is after the eqivalence point

case e: 50.0 mL of 1.00 M NaOH

N_2V_2=50\times1=50

N_1V_1>N_2V_2 hence it is before equivalence point

case f: 200 mL of 1.00 M NaOH

N_2V_2=200\times1=200

N_1V_1 hence it is after the eqivalence point

7 0
4 years ago
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