Answer:
pH = 4.26
Explanation:
Bromocresol green is a commonly used pH indicator. The concentration ratio of the acid form to base form explains its color, which reflects the pH of the medium.
C₂₁H₁₄Br₄O₅S + H₂O ⇄ C₂₁H₁₃Br₄O₅S⁻ + H₃O⁺
acid conjugate base
We can calculate the pH through Henderson-Hasselbalch's equation:
![pH=pKa+log(\frac{[base]}{[acid]} )=4.66+log(\frac{1}{2.49} )=4.26](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%5Cfrac%7B%5Bbase%5D%7D%7B%5Bacid%5D%7D%20%29%3D4.66%2Blog%28%5Cfrac%7B1%7D%7B2.49%7D%20%29%3D4.26)
Answer: 2116.8 seconds
Explanation:
0.0035 weeks × 7days/week × 24hrs/day × 60min/hr × 60sec/min
=2116.8 seconds
=2100 (if you are required to consider significant figures)
Moles of titrant are lost in the calculation in redox titration.
"The process of calculating the quantity of a material A by adding measured increments of substance B, the titrant, with which it reacts until exact chemical equivalency is obtained (the equivalence point)" is the definition of titration.
The equivalence point, or the point at which chemically equivalent amounts of the reactants have been combined, is to be detected by the titration. The stoichiometry of the reaction determines how many reactants have been combined at the equivalence point.
Titration, commonly referred to as titrimetry, is a method of chemical qualitative analysis used to determine the concentration of a certain analyte in a mixture. In the realm of analytical chemistry, titration is a crucial technique.
To learn more about titration please visit- brainly.com/question/16254547
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Checking if it is balanced:
C
3 3
H
8 4*2 = 8
O
8 3*2 + 4 = 6 + 4 = 10
8 10
Only O is not balanced.
So O is violating the law. Option C.
<span>C. O</span>
Answer:
CuFeS2
Explanation:
Calculate the moles of each substance by doing moles= mass/relative atomic mass. you should get 0.25 moles of copper and iron and 0.5 moles of sulfur. Then divide all of those numbers by 0.25 (as its the lowest value) you should get 1 for copper and iron and 2 for sulfur. This represents the ratio that they are in within the mineral.
