Answer:
~3°
Explanation:
x^2 + 0.16^2 = 3^2
x^2 + 0.0256 = 9
x^2 = 8.9744
x = sqrt(8.9744) = 2.99... = ~3
Answer:
The Amount of work is done on the box by the net force is 378 Joules.
Explanation:
Given:
A 42 N net force is applied to a box which slides horizontally across a floor.
Force = 42 N
Force applied for a displacement of 9.0 m
Displacement = 9.0 m
To Find:
Amount of work is done on the box by the net force = ?
i.e Work = ?
Solution:
When a force causes a object to move, work is being done on the object by the force. Work is the measure of energy transfer when a force (F) moves an object through a distance (d).
Formula is given by

Substituting the given values we get
∴ Work = 42 × 9.0
∴ Work = 378 N-m
or
∴ Work = 378 Joules
The Amount of work is done on the box by the net force is 378 Joules.
Answer:
Explanation:
The equation for acceleration is
where vf is the final velocity and v0 is the initial velocity. For us, the final velocity is 25 m/s and the initial is 0 because the train started from resting position. Filling in and solving for a:
so
a = .83 m/s/s