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Tju [1.3M]
3 years ago
12

"Water is absorbed in the intestine through which process"? a. simple diffusion b. active transport c. active diffusion d. facil

itated diffusion e. gradient transport
Physics
1 answer:
sdas [7]3 years ago
6 0

Answer: Water is absorbed in the intestine through gradient transport. The correct option is E.

Explanation:

Absorption of water in the mammalian intestines occurs largely on the small intestine through a transport mechanism known as osmosis. Osmosis is the movement of water molecules, through a semi permeable membrane, from the region of lower solute concentration into higher solute concentration to attain an equilibrium.

For water molecules to be absorbed from the lumen into the bloodstream, it's dependent on sodium absorption. This follows the following steps:

-sodium is absorbed by co transport with glucose and amino acids.this aids to move sodium from lumen into the enterocyte.

- Rapid exportation of absorbed sodium through sodium pimps from the enterocyte.

- As sodium is pumped out of cells an osmotic gradient is formed across apical cell membrane, this helps to osmotically drive water across the epithelium. Therefore water is absorbed in the intestine through the osmotic gradient created by sodium absorption. I hope this helps. Thanks.

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Explanation :

The points regarding the gravitational waves are as follows :

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(3) The existence of gravitational waves is predicted by Einstein's general theory of relativity.

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What was the main idea of Malthus theory of population
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3 years ago
A domestic water heater holds 189 L of water at 608C, 1 atm. Determine the exergy of the hot water, in kJ. To what elevation, in
Gekata [30.6K]

A.

The energy of the hot water is 482630400 J

Using Q = mcΔT where Q = energy of hot water, m = mass of water = ρV where ρ = density of water = 1000 kg/m³ and V = volume of water = 189 L = 0.189 m³,

c = specific heat capacity of water = 4200 J/kg-°C and ΔT = temperature change of water = T₂ - T₁ where T₂ = final temperature of water = 608 °C. If we assume the water was initially at 0°C, T₁ = 0 °C. So, the temperature change ΔT = 608 °C - 0 °C = 608 °C

Substituting the values of the variables into the  equation, we have

Q = mcΔT

Q = ρVcΔT

Q = 1000 kg/m³ × 0.189 m³ × 4200 J/kg-°C × 608 °C

Q = 482630400 J

So, the energy of the hot water is 482630400 J

B.

The elevation <u>the mass would have to be raised from zero elevation relative to the reference environment for its exergy to equal that of the hot water</u> is 49248 m.

Using the equation for gravitational potential energy ΔU = mgΔh where m = mass of object = 1000 kg, g = acceleration due to gravity = 9.8 m/s² and Δh = h - h' where h = required elevation and h' = zero level elevation = 0 m

Since the energy of the mass equal the energy of the hot water, ΔU = 482630400 J

So, ΔU = mgΔh

ΔU = mg(h - h')

making h subject of the formula, we have

h = h' + ΔU/mg

Substituting the values of the variables into the equation, we have

h = h' + ΔU/mg

h = 0 m + 482630400 J/(1000 kg × 9.8 m/s²)

h = 0 m + 482630400 J/(9800 kgm/s²)

h = 0 m + 49248 m

h = 49248 m

So, the elevation <u>the mass would have to be raised from zero elevation relative to the reference environment for its exergy to equal that of the hot water</u> is 49248 m.

Learn more about heat energy here:

brainly.com/question/11961649

5 0
3 years ago
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