How many phase changes does ice undergo when it changes to water vapor in the water cycle?

Write the name of two substance used to laminate the core of transformer

Yakvenalex [24]

Answer:

Transformers use “electrical steel” alloys. ... From 1% to 6.5% silicon is added, as well as a small amount (up to 0.5%) of manganese and aluminum to reduce brittleness in alloys with higher percentages of silicon. Electrical steels are formulated and processed to have low hysteresis and eddy-current losses.

Explanation:

The eddy currents consume energy and heat the iron core. The designers of the electrical machines and transformers laminate the core with thin sheets of iron coated with a thin oxide layer.

8 0

3 years ago

Complete all four parts. 15 points. Will give brainliest! Show work!

Vlada [557]

Answer:

A. 5.08 secs.

B. 10.16 secs.

C. 126.50 m.

D. 373.36 m

Explanation:

Data obtained from the question include the following:

Initial velocity (u) = 65 m/s

Angle of projection θ = 50°

A. Determination of the time taken to reach the peak.

Initial velocity (u) = 65 m/s

Angle of projection θ = 50°

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =.?

t = u•Sine θ/g

t = (65 × Sine 50) /9.8

t = 5.08 secs.

B. Determination of the total time spent by the ball in air.

Time (t) taken to reach the peak = 5.08 secs.

Total time (T) spent by the ball in air =?

T = 2t

T = 2 × 5.08

T = 10.16 secs

Therefore, the total time spent by the ball in air is 10.16 secs.

C. Determination of the maximum height.

Initial velocity (u) = 65 m/s

Angle of projection θ = 50°

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (H) =..?

H = u²•Sine² θ / 2g

H = 65² × (Sine 50)² / 2 × 9.8

H = 4225 × (Sine 50)² /19.6

H = 126.50 m

Therefore, the maximum height reached by the ball is 126.50 m.

D. Determination of the horizontal distance travelled by the ball.

Initial velocity (u) = 65 m/s

Angle of projection θ = 50°

Acceleration due to gravity (g) = 9.8 m/s²

Horizontal distance (R) =..?

R = u²•Sine 2θ / g

R = 65² × Sine (2×30) / 9.8

R = (4225 × Sine 60) / 9.8

R = 373.36 m

Therefore, the horizontal distance travelled by the ball is 373.36 m

6 0

3 years ago

I need help with this one <br><br> Coulombs law <br><br> 100 points and brainliest

Ganezh [65]

Answer:

my dad is a physics professor so when he comes home i will tell him to answer the question for you

3 0

3 years ago

Read 2 more answers

A 1.00 -kg object slides to the right on a surface having a coefficient of kinetic friction 0.250 (Fig. P8.62a). The object has

LekaFEV [45]

The distance D where the object comes to rest is 1.08.m.

<h3>What is the distance?</h3>

The separation of one thing from another in space; the distance or separation in space between two objects, points, lines, etc.; remoteness. The distance of seven miles cannot be accomplished in one hour of walking.
Learn how to use the Pythagorean theorem to get the separation between two points using the distance formula. The Pythagorean theorem can be rewritten as d==(((x 2-x 1)2+(y 2-y 1)2)
The distance between any two places is the length of the line segment separating them. By measuring the length of the line segment that connects the two points in coordinate geometry, the distance between them may be calculated.

(c) the distance D where the object comes to rest.

$W_{total} =$ ΔKE ⇒ -0.25*1*9.8*D = 0-1/2*1* $2.3^{2}$

⇒ $D=\frac{0.5*2.3^{2} }{2.45}$

⇒1.08.m

To learn more about distance, refer to:

brainly.com/question/4998732

#SPJ4

5 0

2 years ago

A skateboarder shoots off a ramp with a velocity of 6.6 m/s, directed at an angle of 58 above the horizontal. The end of the ram

sweet-ann [11.9K]

Answer:

a) Maximum height reached above ground = 2.8 m

b) When he reaches maximum height he is 2 m far from end of the ramp.

Explanation:

a) We have equation of motion v²=u²+2as

Considering vertical motion of skateboarder.

When he reaches maximum height,

u = 6.6sin58 = 5.6 m/s

a = -9.81 m/s²

v = 0 m/s

Substituting

0²=5.6² + 2 x -9.81 x s

s = 1.60 m

Height above ground = 1.2 + 1.6 = 2.8 m

b) We have equation of motion v= u+at

Considering vertical motion of skateboarder.

When he reaches maximum height,

u = 6.6sin58 = 5.6 m/s

a = -9.81 m/s²

v = 0 m/s

Substituting

0= 5.6 - 9.81 x t

t = 0.57s

Now considering horizontal motion of skateboarder.

We have equation of motion s =ut + 0.5 at²

u = 6.6cos58 = 3.50 m/s

a = 0 m/s²

t = 0.57

Substituting

s =3.5 x 0.57 + 0.5 x 0 x 0.57²

s = 2 m

When he reaches maximum height he is 2 m far from end of the ramp.

8 0

4 years ago