Answer:
Tectonic plate interactions are of three different basic types: Divergent boundaries are areas where plates move away from each other, forming either mid-oceanic ridges or rift valleys. These are also known as constructive boundaries. Convergent boundaries are areas where plates move toward each other and collide.
Explanation:
Meaning the answer to your question is depending on what type of tectonic plate interaction is occurring will depend on how the plates interact.
Answer:
7.75%
Explanation:
mass of climber, m = 55 kg
height, h = 701 m
Qc = 4.5 x 10^6 J (heat exhaused by the body)
Work = m x g x h
W = 55 x 9.8 x 701
W = 377839 J
W = QH - Qc
Where, QH is the heat input
QH = 377839 + 4.5 x 10^6
QH = 4877839 J
So, the efficiency
e = W / QH
e = 377839 / 4877839
e = 0.0774 = 7.75 %
Thus, the efficiency of the body is 7.75 %.
I think the right answer for this question is : 138 because the boy is just 15 year old but he has resting heart rate of 70
Answer:
at y=6.29 cm the charge of the two distribution will be equal.
Explanation:
Given:
linear charge density on the x-axis, 
linear charge density of the other charge distribution, 
Since both the linear charges are parallel and aligned by their centers hence we get the symmetric point along the y-axis where the electric fields will be equal.
Let the neural point be at x meters from the x-axis then the distance of that point from the y-axis will be (0.11-x) meters.
<u>we know, the electric field due to linear charge is given as:</u>

where:
linear charge density
r = radial distance from the center of wire
permittivity of free space
Therefore,





∴at y=6.29 cm the charge of the two distribution will be equal.
Complete question:
The exit nozzle in a jet engine receives air at 1200 K, 150 kPa with negligible kinetic energy. The exit pressure is 80 kPa, and the process is reversible and adiabatic. Use constant specific heat at 300 K to find the exit velocity.
Answer:
The exit velocity is 629.41 m/s
Explanation:
Given;
initial temperature, T₁ = 1200K
initial pressure, P₁ = 150 kPa
final pressure, P₂ = 80 kPa
specific heat at 300 K, Cp = 1004 J/kgK
k = 1.4
Calculate final temperature;

k = 1.4

Work done is given as;

inlet velocity is negligible;

Therefore, the exit velocity is 629.41 m/s