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Leni [432]
2 years ago
6

Foraging bees often move in straight lines away from and toward their hives. Suppose a bee starts at its hive and flies 500 m du

e east, then flies 440 m west, then 690 m east. How far is the bee from the hive?
Physics
1 answer:
elena55 [62]2 years ago
3 0

The bee is 750 m due east from its hive.

<h3>Displacement of the bee from its hive</h3>

The displacement of an object is the change in the position of an object.

net displacement in eastward direction = 500 m east + 690 m east = 1190 m east

net displacement in westward direction = 440 m west

<h3>Total displacement of the bee from its hive</h3>

Displacement = 1190 m east - 440 m west = 750 m east

Thus, the bee is 750 m due east from its hive.

Learn more about displacement here: brainly.com/question/2109763

#SPJ1

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The gravitational force between two asteroids is 2.59 × 10 (exponent)-6 N. The centers of mass are 2000 meters away and their ma
makkiz [27]

Answer:

2.79 \times 10^5 \ \text{kg}

Explanation:

Newton's Law of Universal Gravitation:

  • $F= G\frac{m_1 m_2}{r^2}
  • F = force of gravity (N)
  • G = gravitational constant (6.67 \times 10^-^1^1 \ N\frac{m^2}{kg^2})
  • m_1 = mass of Object 1 (kg)
  • m_2 = mass of Object 2 (kg)
  • r = distance between the center of mass (m)

Let's convert our given information to scientific notation:

  • 2000 \ m \rightarrow 2.0 \times 10^3 \ m

Now using the gravitational force and the distance between centers of mass that are given, we can plug these into Newton's law:

  • 2.59 \times 10^-^6 $\ N = 6.67 \times 10^-^1^1 \ N \frac{m^2}{kg^2}  \times \frac{m_1 m_2}{(2.0 \times 10^3 \ m)^2}

Remove the units for better readability.

  • 2.59 \times 10^-^6=6.67 \times 10^-^1^1 \frac{m_1m_2}{(2.0 \times 10^3)^2}

Divide both sides of the equation by the gravitational constant G.

  • \frac{2.59 \times 10^-^6}{6.67 \times 10^-^1^1} =\frac{m_1m_2}{(2.0 \times 10^3)^2}

Distribute the power of 2 inside the parentheses.

  • \frac{2.59 \times 10^-^6}{6.67 \times 10^-^1^1} =\frac{m_1m_2}{2.0 \times 10^6}

If we evaluate the left side of the equation, we get:

  • 3.88305847 \times 10^4 = \frac{m_1m_2}{2.0 \times 10^6}

Multiply both sides of the equation by r.

  • 7.76611694 \times 10^1^0= m_1m_2

In order to find the mass of one asteroid, we can use the fact that both asteroids have the same mass, therefore, we can rewrite m_1m_2 as m^2.

  • 7.76611694 \times 10^1^0= m^2

Square root both sides of the equation.

  • m=\sqrt{7.76611694 \times 10^1^0}
  • m=2.78677536 \times 10^5
  • m=2.79 \times 10^5

Since m is in units of kg, we can state that the mass of each asteroid is 2.79 * 10⁵ kg.

3 0
3 years ago
B. A car moving at an initial speed vi applies its brakes and skids for some distance until coming to a complete stop. If the co
wariber [46]

Complete Question

The complete question is  shown on the first uploaded image  

Answer:

The distance which the car skid is  l  =  \frac{v_i^2 }{2 *  \mu_k  * g }

Explanation:

From the question we are told that  

     The  initial velocity of the car is  v_i

     The  coefficient of kinetic friction is  \mu_k

According to the law of energy conservation

    The initial Mechanical Energy =  The final  Mechanical Energy  

                           M_i  = M_f  

The initial mechanical energy is  mathematically represented as  

              M_i  =  KE _o  + PE_e

where KE is the initial kinetic energy which is  mathematically represented as

        KE  =  \frac{1}{2} m v_i^2

And  PE  is  the initial potential energy which is  zero given that the car is  on the ground

     Now  

           M_f =  W_{\mu}

Where  W_{\mu} is  the work which friction exerted on the car  which is  mathematically represented as

       W_{\mu} =  m*  \mu_k  *  g  *  l

Where  l is the distance covered by the car before it slowed down

        \frac{1}{2} m v_i^2  = m*  \mu_k  *  g * l

=>     l  =  \frac{v_i^2 }{2 *  \mu_k  * g }

                 

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Answer:

2

Explanation:

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The parameters used to describe a particular trait or characteristic in a human behavior should be reliable and valid, in order to determine the response of the population with respect to a particular stimulus.

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