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sergij07 [2.7K]
3 years ago
10

Whitch family has full valence energy level

Physics
1 answer:
levacccp [35]3 years ago
7 0
Group 0 - they are called the NOBLE GASES
(as they're very unreactive) because...

ALL of their atoms are full.
Example : Helium contains 2 electrons so it's outer shell is full
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What is the kinetic energy of an object that has a mass of 12 kilograms and moves with a velocity of 10 m/s?
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1/2mv^2

1/2x12x10^2=600J

The kinetic energy is 600J
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In a controlled experiment, which variable does the investigator change?
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Answer:

The manipulated variable is also known as the independent variable

Explanation:

When remembering this remember independent as in you independently change the outcome

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A spring is stretched 2.0 cm. If the same spring is stretched 8.0 cm the ratio of the second and first potential energies of the
jok3333 [9.3K]
Potential energy of spring equals K times X squared divided by 2 where X is displacement

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6 0
3 years ago
Use the information from the graph to answer the question. What is the acceleration of the object
Art [367]

Answer:

-2.5 m/s²

Explanation:

The acceleration of a body is the change in it's velocity with time.

The change in velocity with time can be obtained as the slope of a velocity time graph ;

Acceleration = (change in velocity / change in time)

Taking the slope :

Change in Velocity = △y = y2 - y1

Change in time = △x = x2 - x1

(10, 15) ; (0, 40)

△y / △x = y2 - y1 / x2 - x1 = (40 - 15) / (0 - 10)

△y / △x = 25 / - 10 = - 2.5 m/s²

4 0
3 years ago
A car of mass 1000 kg travelling at a velocity of 25 m/s collides with another car of mass 1500kg which is at rest. The two cars
Svetach [21]

Answer:

<em>The velocity of the two cars is 10 m/s after the collision.</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is

P=m.v

If we have a system of bodies, then the total momentum is the sum of them all

P=m_1v_1+m_2v_2+...+m_nv_n

If some collision occurs, the velocities change to v' and the final momentum is:

P'=m_1v'_1+m_2v'_2+...+m_nv'_n

In a system of two masses, the law of conservation of linear momentum  takes the form:

m_1v_1+m_2v_2=m_1v'_1+m_2v'_2

If both masses stick together after the collision at a common speed v', then:

m_1v_1+m_2v_2=(m_1+m_2)v'

The car of mass m1=1000 Kg travels at v1=25 m/s and collides with another car of m2=1500 Kg which is at rest (v2=0).

Knowing both cars stick and move together after the collision, their velocity is found solving for v':

\displaystyle v'=\frac{m_1v_1+m_2v_2}{m_1+m_2}

\displaystyle v'=\frac{1000*25+1500*0}{1000+1500}

\displaystyle v'=\frac{25000}{2500}

v' = 10 m/s

The velocity of the two cars is 10 m/s after the collision.

4 0
3 years ago
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