Answer:
25
Step-by-step explanation:
<ABD=<BDC
Check it out
You can solve this problem through factoring.
First, you have the equation,

Then, you can factor the numerator.

You can cancel out the x-6 in both the numerator and the denominator because they would equal to just 1.
You are left with 
The function is removable noncontinuous at x=6 because if you plug in 6 in x-6, your denominator would be undefined.
Hello!
Let's think about the denominators we have. A seventh goes on forever in no specified order. A fifth an a fourth have set decimal values, 0.2 and 0.25, so they are not repeating decimals. A ninth is 0.111111..., it repeats like this forever in a specified order. Therefore, 2/9, or 0.222222...., would be a repeating decimal.
Therefore, our answer is
.
I hope this helps!
5+4 = 10 - 1
the missing number is 1