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emmainna [20.7K]

1 year ago

6

A company gives each worker a cash bonus every Friday, randomly giving a worker an amount with these probabilities: $10 - 0.75,

$50 - 0.25. Over many weeks, what is a worker's expected weekly bonus?
1. 10 x 0.25 + 50 x 0.75 = $40
2. (10 + 50) x (0.75 x 0.25) = $11.5
3. 10 x 0.75 + 50 x 0.25 = $20
4. Cannot say as the number of weeks is not provided.

1 answer:

vredina [299]1 year ago

4 0

Answer:

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$a'(d) = \frac{d}{5} + \frac{3}{5}$

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Step-by-step explanation:

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Solving (a): Write as inverse function

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To do this, we prove that:

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Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

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