Help ! 7p^2-38p-24=0

2 answers:

8 0

<span>7p^2-38p-24=0

All you need is to factor it, as follows

(7p + 4) (p - 6) = 0

Use FOIL to make sure that you got the correct factoring

Hope that helps
</span>

ivolga24 [154]3 years ago

6 0

What is this. what are post to do.

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the sum of three numbers is 128.The third number is 10 more than the first .The second number 4 times the third number. what are

Ray Of Light [21]

128 = a + + 4(a + 10) + (a + 10)
128 = a + 4a + 40 + a + 10
128 = 6a + 50
128-50 = 6a
78 = 6a
13 = a

1st = a = 13
2nd = 4(a + 10) = 4(23) = 92
3rd = a + 10 = 23

3 0

3 years ago

Solve x2-8x=3 by completing the square. which is the solution set of the equation

Mazyrski [523]

we have

$x^{2}-8x=3$

Complete the square. Remember to balance the equation by adding the same constants to each side

$x^{2}-8x+16=3+16$

$x^{2}-8x+16=19$

Rewrite as perfect squares

$(x-4)^{2}=19$

$(x-4)^{2}=19\\ (x-4)=(+/-)\sqrt{19} \\ \\ x1=4+\sqrt{19} =8.359\\ x2=4-\sqrt{19} =-0.359$

therefore

the answer is

$x1=4+\sqrt{19} =8.359\\x2=4-\sqrt{19} =-0.359$

5 0

3 years ago

Read 2 more answers

Line segment WX is the radius of circle X, and line segment ZY is the radius of circle Y. Points W, X, C, Y, and Z are all on li

Andrews [41]

Point D is the midpoint of the outer circle that we aim to find the area of

The circle has a diameter of WZ and radii of WC and CZ

We know that YZ=YD=10 cm

Let DC be $x$ and CY be $10-x$

The radius of the outer circle can be written as $8+8+x$ or $10+10-x$ which we can equate to find the value of $x$

$8+8+x=10+10-x$
$16+x=20-x$
$2x=4$
$x=2$

Therefore, the radius of the circle is $8+8+2=18$

And hence the area of the circle is $\pi (18^{2})$ =324 $\pi$