128 = a + + 4(a + 10) + (a + 10) 
128 = a + 4a + 40 + a + 10
128 = 6a + 50
128-50 = 6a
78 = 6a
13 = a
1st = a = 13
2nd = 4(a + 10) = 4(23) = 92
3rd = a + 10 = 23
        
             
        
        
        
we have

Complete the square. Remember to balance the equation by adding the same constants to each side


Rewrite as perfect squares


therefore
the answer is

 
        
                    
             
        
        
        
Point D is the midpoint of the outer circle that we aim to find the area of
The circle has a diameter of WZ and radii of WC and CZ
We know that YZ=YD=10 cm
Let DC be 

 and CY be 

The radius of the outer circle can be written as 

 or 

 which we can equate to find the value of 





Therefore, the radius of the circle is 

And hence the area of the circle is 

=324
 
 
        
        
        
Answer:
correct
Step-by-step explanation:
Imagine a point in the top left quadrant of a graph
when you rotate it 180 degrees it will end up in the bottom right quadrant 
The same will apply if you flip on the y axis and the x axis in no given order