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Tcecarenko [31]
2 years ago
6

Someone please help me

Mathematics
2 answers:
Hoochie [10]2 years ago
7 0
I think it might be point be but I’m not sure if it’s correct I’m sorry if it’s wrong
Lynna [10]2 years ago
7 0

Answer: I would say C indefinitley

Step-by-step explanation:

Because If you add by 1.5 to each line it just makes it there. It says <u>Approximate</u> to 59.

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Can you Help me place
Ratling [72]

Answer:

P(w) = 9w+5

Step-by-step explanation:

You see every week there is an increase of 9, and it starts at 5. That's all you need to know for a linear equation.

3 0
3 years ago
Read 2 more answers
Sandy's orchard has only 4 apple trees for every 3 pear trees. She is wanting to plant enough avocado trees so that she has 2 av
LUCKY_DIMON [66]
<span>current ratio: 4 apple trees for every 3 pear trees. wants: 2 avocado trees for every 5 pear trees in the orchard. Sandy is planting 18 avocado trees so 2 avocado trees for every 5 pear trees =1 avocado trees for every 2.5 pear trees therefore if we have 18 avocado trees 18 x 2.5 = 45 pear trees 4 apple trees for every 3 pear trees 4/3 = 1.333 apple trees for every 1 pear tree therefore if we have 45 avocado trees 45 x 1.333 = 60 apple trees therefore ratio of avocado to apple trees = 18 : 60 18 : 60 = 9 : 30 = 3 : 10</span>
4 0
3 years ago
I NEED HELP!! please show all work
PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

4^{5x} = 3^{x-2}

\implies \log 4^{5x} = \log 3^{x-2}

Drop the exponents:

\implies 5x \log 4 = (x-2) \log 3

Expand the right side:

\implies 5x \log 4 = x \log 3 - 2 \log 3

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :

\implies 5x \log 4 - x \log 3 = - 2 \log 3

\implies x (5 \log 4 - \log 3) = - 2 \log 3

Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}

You can stop there, or continue simplifying the solution by using properties of logarithms:

\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }

\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }

\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}

You can condense the solution further using the change-of-base identity,

\implies \boxed{x = -\log_{\frac{1024}3}9}

5 0
2 years ago
there are 28 tables in the cafeteria.each table has 12 students sitting at it.fourth graders sit at 13 of the yables.fifth grade
Darya [45]
Hope this helps!

28 - 13 = 15
15 x 12 = 180 Fifth graders
6 0
3 years ago
Sandra throws an object into the air with an initial vertical velocity of 38 feet per second, from a platform that is 30 feet ab
Lina20 [59]
It will take the object 3 s
4 0
3 years ago
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