Solve the trinomial 10b2 +17b + 3

Mathematics

1 answer:

Jet001 [13]3 years ago

3 0

27b2+3 is the answer because 2 isnt an exponent which make 10 and 17 addable

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Kisachek [45]

Answer:
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The simplied version is:
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" $\frac{3v(v^2+7)}{(v^2+13v+42)}$ " ;

or; write as: " $\frac{3v(v^2+7)}{(v+7)(v+6)}$ " .
_______________________________________________
Explanation:
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Given:
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" $\frac{6v^3 +42 v}{2v^2 +26v + 84}$ " ;
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→ Factor out a "6v" $\frac{6v(v^2+7)}{2(v^2+13v+42)}$ in the "numerator"; & factor out a "2" in the denominator; as follows:
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→ $\frac{6v(v^2+7)}{2(v^2+13v+42)}$ ;
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→ " $\frac{3v(v^2+7)}{(v^2+13v+42)}$ " ;
______________________________________________

or; factor out the "denominator" :
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and write as:
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→ " $\frac{3v(v^2+7)}{(v+7)(v+6)}$ " .
______________________________________________

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