Given :
We know the identity
We use this property to simplify the left hand side
So 
we know ,
when 
then
For
Add 
on both sides
Finally we add 2npi for general solution
So options C and D are correct
Answer:
c
Step-by-step explanation:
8 student out of 24 are female so that should be the answer
Answer:
160,000 tins
Step-by-step explanation:
To find the number of tins, divide the fill rate by the volume per tin.
__
(2·(1000 L)/min)×(60 min)/(1 h)/(0.75 L/tin) = 160,000 tin/h
160,000 tins of paint can be filled in 1 hour.
_____
<em>Additional comment</em>
That's one tin every 22.5 milliseconds. It would be a feat of engineering to move that volume without splashing.
There are 60 minutes per hour. There are 1000 liters per cubic meter.
Answer:
Option A: P ≈ 38.7 in, A ≈ 63.7 in²
Step-by-step explanation:
We are told that △MNO ~△DEF. This means that they are similar triangles.
We can solve for this using scale factor.
a) Perimeter of △MNO
The scale factor of two similar triangles is equal to the ratio of the perimeter of the triangles
Scale factor(k) = ratio of the sides of the triangles
In the diagram we are given
Side of △MNO = 6.7in
Side of △DEF = 9in
Perimeter of △MNO = X
Perimeter of △DEF = 52in
Scale factor (k) = 6.7/9
Hence,
6.7/ 9 = X/52
Cross Multiply
9X = 6.7 × 52
X = 6.7 × 52/9
X = 38.711111111 inches
To the nearest tenth, Perimeter of △MNO = 38.7 inches
b) Area of △MNO
The square of the scale factor of two similar triangles is equal to the ratio of area of the triangles
Scale factor(k) = ratio of the sides of the triangles
In the diagram we are given
Side of △MNO = 6.7in
Side of △DEF = 9in
Area of △MNO = Y
Area of △DEF = 115in²
Scale factor (k) = 6.7/9
Hence,
(6.7/ 9)² = Y/115
6.7²/9² = Y / 115
Cross Multiply
9² × Y = 6.7² × 115
Y = 6.7²× 115 /9²
Y = 63.732716049 square inches
To the nearest tenth, Area of △MNO = 63.7 in²
