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aev [14]
3 years ago
14

Please help, I would appreciate it thank you :)

Mathematics
1 answer:
Inessa [10]3 years ago
7 0

Answer:

<h3>HERE IS YOUR ANSWER FRIEND,</h3><h3><em>HOPE</em><em> </em><em>IT</em><em> </em><em>HELPED</em><em> </em><em>YOU</em><em>,</em></h3><h2>PLEASE MARK ME AS <em><u>BRAINLIST</u></em><em><u> </u></em></h2>

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What’s the answer to this
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2.4/0.3=8
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The scale factor is 8.
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2 years ago
Which expression is equivalent to 4(5j + 7)?
frozen [14]

Answer: 4(5j+7) = 20j+28

Step-by-step explanation:

5 0
2 years ago
I dentist the slope and a point on the line
Anika [276]

Answer:

2/3 (0,-3) is one possible answer.

Step-by-step explanation:

y  -1 = 2/3(x-6)  We want to get this into the slope intercept form of a line.  We want it to be in the form y = mx + b.  Let's clear the fraction first by multiplying the whole equation through by 3.

3(y - 1) = 3[2/3(x - 6)]

3y -3 = 2(x -6)

3y - 3 = 2x -12

3y = 2x - 9  Now divide all the way through by 3 to get

y = 2/3x - 3  

y = mx + b.  The m part is the slope.  In this equation the slope is 2/3

There are in infinite amount of points on a line.  I do not know if they give you a picture or if you are just to create your own.  I am going to create a point that have x = 0.  I get to pick the point.  I could pick any number.  0 is just usually really easy.  So, if I substitute 0 for x I will get:

y = 2/3(0) - 3

y = 1  so my point is (0,-3)

Now that I think about it, I do not think that I would start out clearing the fraction even though it works.  I think that I would do it like this"

y - 1 = 2/3(x - 6)  Distribute the 2/3 through (x - 4) to get

y-1 = 2/3x -4  I can make -6 a fraction by putting it over 1.  Now we have 2/3(-6/1)  multiply across to get  -12/3.  A positive times a negative is a negative.  -12 divided by 3 is -4.

y - 1 = 2/3x -4   now add 1 to both sides.

y = 2/3x -3

6 0
1 year ago
Which quadratic function in vertex form can be represented by the graph that has a vertex at (3, -7) and passes through the poin
yarga [219]

~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill

\begin{cases} h=3\\ k=-7 \end{cases}\implies y=a(x-3)^2-7\qquad \textit{we also know that} \begin{cases} x=1\\ y=-10 \end{cases} \\\\\\ -10=a(1-3)^2-7\implies -3=a(-2)^2\implies -3=4a\implies -\cfrac{3}{4}=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y=-\cfrac{3}{4}(x-3)^2-7~\hfill

5 0
1 year ago
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