Answer:
Step-by-step explanation:
hello : write this expression
X² + y² + 6x – 2y+3 = 0 in the standard form
(x²+6x) +(y²-2y) +3 = 0
(x²+6x+9 -9) +(y²-2y+1 - 1) +3 = 0
(x²+6x+9) -9 +(y²-2y+1) - 1 +3 = 0
(x+3)²+(y-1)² = 7(the standard form)
but : 7 = (√7)²
<h2>the radius is :
√7</h2>
After 1 year, the initial investment increases by 7%, i.e. multiplied by 1.07. So after 1 year the investment has a value of $800 × 1.07 = $856.
After another year, that amount increases again by 7% to $856 × 1.07 = $915.92.
And so on. After t years, the investment would have a value of
.
We want the find the number of years n such that

Solve for n :





I think It is be but idk as I am in year 7
Answer:
3x +5+2x+44+110+123+136=360
5x+418=360
c. l. t
5x=58
therefore X=11.5