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Levart [38]
3 years ago
7

How many moles of nitrogen gas are in a flask with a volume of 0.25 L at a pressure of 2.96 atm and a temperature of 300 K

Chemistry
1 answer:
aniked [119]3 years ago
6 0

<u>Answer:</u> The number of moles of nitrogen gas is 0.030 moles

<u>Explanation:</u>

To calculate the number of moles of nitrogen, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the nitrogen gas = 2.96 atm

V = Volume of the gas = 0.25 L

T = Temperature of the gas = 300 K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles of nitrogen gas = ?

Putting values in above equation, we get:

2.96atm\times 0.25L=n\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 300K\\\\n=\frac{2.96\times 0.25}{0.0821\times 300}=0.030mol

Hence, the number of moles of nitrogen gas is 0.030 moles

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Mass of the shells will remain constant.

Explanation:

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The texture or chemical properties of the microscopic shell get changed. but the amount of microscopic shell deposited to make sedimentary rocks remains the same.

Chalk and coral reefs are the example of sedimentary rocks made up with microscopic shells.

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3 0
4 years ago
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Convert to moles:<br> 100.0g Ca3(PO4)2
salantis [7]

Answer:

0.322 moles

Explanation:

Given Mass, m = 100 g

The molar mass of Ca₃(PO₄)₂

Ca₃(PO₄)₂ = (3 x 40.08) + (2 x 30.97) + (8 x 16.00)

M = 310.18 g/mol

Let there are n number of moles,

n = given mass/ molar mass

n=\dfrac{100 }{310.18 }\\\\n=0.322\ mol

So, there are 0.322 moles.

6 0
3 years ago
How to extract salt from salt water
Vadim26 [7]

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2 years ago
What is the molality of the resulting solution when 15.0 g of Licl is combined with 105 g of water? 0/1 point 0 1.42 m 2.95 m 3.
xenn [34]

Answer:

3.37 m

Explanation:

<u>Number of moles of solute present in 1 kg of solvent is termed as molality</u>

It is represented by 'm'.

Thus,

Molality\ (m)=\frac {Moles\ of\ the\ solute}{Mass\ of\ the\ solvent\ (kg)}

Given that:

The mass of LiCl = 15.0 g

Molar mass of LiCl = 42.394 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{15.0\ g}{42.394\ g/mol}

Moles= 0.3538\ mol

Mass of the solvent = 105 g

Also, 1 g = 0.001 g

So,

Mass of water (solvent) = 0.105 kg

Molality is:

Molality\ (m)=\frac {0.3538}{0.105}\ m

<u>Molality = 3.37 m</u>

3 0
3 years ago
There are 15 technicians and 11 chemists working in a research laboratory. In how many ways could they form a 5-member safety co
Fynjy0 [20]

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5 0
3 years ago
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