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wolverine [178]

3 years ago

10

Balanced Equation: C3H8 + 502 → 3CO2 + 4H20 How many grams of CO 2 can be produced with 13.1 L of O2? (If your answer is in scie

ntific notation, use 'e. Example, 6.02X1023 would be 6.02e23)

1 answer:

noname [10]3 years ago

5 0

Answer:

3CO2 + 4H20

Explanation:

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What is the overall equation for this chemical reaction?

ahrayia [7]

Answer:

Mg(s) + 2H⁺ → Mg²⁺(aq) + H₂.

Explanation:

To obtain the overall reaction, we sum the two half-reactions and omit the similar species in the reactants and products sides.

We have two reactions:

oxidation reaction:

Mg(s) → Mg²⁺(aq) + 2e.

Reduction reaction:

2H⁺ + 2e → H₂.

So, we add the two half-reactios and obtain the overall reaction:

<em>Mg(s) + 2H⁺ → Mg²⁺(aq) + H₂.</em>

<em></em>

3 0

4 years ago

A 420 mL sample of a 0.100 M formate buffer, pH 3.75, is treated with 7 mL of 1.00 M KOH. What is the pH following this addition

Art [367]

<u>Answer:</u> The pH of the resulting solution will be 3.60

<u>Explanation:</u>

Molarity is calculated by using the equation:

$\text{Molarity}=\frac{\text{Moles}}{\text{Volume}}$ ......(1)

We are given:

Molarity of formic acid = 0.100 M

Molarity of potassium formate = 0.100 M

Volume of solution = 420 mL = 0.420 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

$\text{Moles of formic acid}=(0.100mol/L\times 0.420L)=0.0420mol$

$\text{Moles of potassium formate}=(0.100mol/L\times 0.420L)=0.042mol$

Molarity of KOH = 1.00 M

Volume of solution = 7 mL = 0.007 L

Putting values in equation 1, we get:

$\text{Moles of KOH}=(1mol/L\times 0.007L)=0.007mol$

The chemical equation for the reaction of formic acid and KOH follows:

$HCOOH+KOH\rightleftharpoons HCOOK+H_2O$

I: 0.042 0.007 0.042

C: -0.007 -0.007 +0.007

E: 0.035 - 0.049

Volume of solution = [420 + 7] = 427 mL = 0.427 L

To calculate the pH of the acidic buffer, the equation for Henderson-Hasselbalch is used:

$pH=pK_a+ \log \frac{\text{[conjugate base]}}{\text{[acid]}}$ .......(2)

Given values:

$[HCOOK]=\frac{0.049}{0.427}$

$[HCOOH]=\frac{0.035}{0.427}$

$pK_a=3.75$

Putting values in equation 2, we get:

$pH=3.75-\log \frac{(0.049/0.427)}{(0.035/0.427)}\\\\pH=3.75-0.146\\\\pH=3.60$

Hence, the pH of the resulting solution will be 3.60

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3 years ago

Islands have cool and calm weather throughout the year? Why?

saveliy_v [14]

There’s no one around and the breeze from the Ocean makes it cool

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What molecules can form hydrogen bonds?

wlad13 [49]

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6 0

4 years ago

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Do you know that Jesus Loves you ? If you dont know now that he does and always has and you've always had God' Grace

Zolol [24]

Sorry, I don’t believe in Jesus or god etc but thnx???

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3 years ago