3 years ago

Solve 7y-6=2y+8 show clear algebraic working

2 answers:

7 0

7y - 6 = 2y + 8

put similar terms on one side of the equation

transpose 2y
7y - 2y - 6 = 8

transpose -6
7y - 2y = 8 + 6

operate/simplify
5y = 14
[5y = 14] (1/5)

y = 14/5

aniked [119]3 years ago

5 0

1) subtract 2y in both sides: (7y-2y)-6=(2y-2y)+8 which is 5y-6=8
2) Add 6 to both sides: 5y(-6+6)=8+6 which is 5y=14
3) Divide 5 on both sides: 5y/5=14/5 which is y=14/5 or y=2.8 or y=2 4/5

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2 years ago

If thewronskian w of f and g is 3e4t,and if f(t) = e2t,find g(t).

ehidna [41]

$W(f(x),g(x))=\begin{vmatrix}f(x)&g(x)\\f'(x)&g'(x)\end{vmatrix}=f(x)g'(x)-g(x)f'(x)$

We have $f(t)=e^{2t}\implies f'(t)=2e^{2t}$ , so

$W(f(t),g(t))=e^{2t}g'(t)-2e^{2t}g(t)=3e^{4t}$
$\implies e^{-2t}g'(t)-2e^{-2t}g(t)=3$
$\implies\dfrac{\mathrm d}{\mathrm dt}[e^{-2t}g(t)]=3$
$\implies e^{-2t}g(t)=\displaystyle\int3\,\mathrm dt$
$\implies e^{-2t}g(t)=3t+C$
$\implies g(t)=3te^{2t}+Ce^{2t}$

where $C$ is any arbitrary constant.