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WINSTONCH [101]
3 years ago
5

5x-3y=-12 in slope-intercept form

Mathematics
2 answers:
Likurg_2 [28]3 years ago
6 0
5x-3y= -12
-3y= -12 - 5x Move 5x to the right side
3y= 12 + 5x Change signs on both sides
y= 4 + 5/3x Divide both sides by 3
y= 5/3x + 4 Rewrite

y= 5/3x +4 Answer

If you don’t mind, please give me brainliest!
madreJ [45]3 years ago
4 0

Answer:

Subtract 5x from both sides of the equation

-3y = 12 - 5x

Then, divide each term by -3 and simplify.

y = -4 + 5x

           ------

              3

After that, you'll do this

y= 5x

   ----- - 4

     3

Lastly, you put that into slope-intercept form.

y = 5

    ---- x - 4

     3

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What is the equation of the line passing through the points (4, -7.5) and (6, -3.5) in slope-intercept form?
Ratling [72]

Answer:

Your answer will be

y=2x-15.5

Step-by-step explanation:

Hi, there you must know the slope-intercept form which is

y=mx+b

m=slope

b=y-intercept

You can also use

the slope formula which is

\frac{y_2-y_1}{x_2-x_1}

in this case

it will look like this

\frac{-7.5-(-3.5)}{6-4}=\frac{-4}{2}=-2

So the slope is -2

Now we will find the y-intercept

-7.5=2(4)+b

-7.5=8+b   Subtract 8 both sides

-15.5=b

Your y-intercept is -15.5

Hope this helps

6 0
3 years ago
1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING
iogann1982 [59]

If

y=\displaystyle\sum_{n=0}^\infty a_nx^n

then

y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n

The ODE in terms of these series is

\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0

\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0

\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}

We can solve the recurrence exactly by substitution:

a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0

\implies a_n=\dfrac{(-2)^n}{n!}a_0

So the ODE has solution

y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}

which you may recognize as the power series of the exponential function. Then

\boxed{y(x)=a_0e^{-2x}}

7 0
3 years ago
This stuff confuses me
Slav-nsk [51]
It's slope would be undefined.
6 0
3 years ago
Read 2 more answers
What value of n makes the equation true?
Naddik [55]

Answer:

n = 5.2.

Step-by-step explanation:

-20.8 = -4n

We divide both sides of the equation by -4:

-20.8 / -4 = -4n/-4

5.2 = n  (answer).

4 0
3 years ago
Read 2 more answers
Solve the inequality 2(4x+1)<3(2x-3)
Ostrovityanka [42]

Answer:

X<-11/2

Step-by-step explanation:

Hope I helped:)

5 0
3 years ago
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