Option C is correct because it is a trinomial with a leading coefficient of 3 and a constant term of -5
Step-by-step explanation:
We need to pick the expression that matches this description:
A trinomial with a leading coefficient of 3 and a constant term of -5
First lets explain the terms:
Trinomial: a polynomial having 3 terms
Leading coefficient: The constant value of variable having highest power
Constant term: Having no variable and value cannot be changed.
Now using these definitions, we can choose the correct option
Option A is incorrect because the expression has 2 terms
Option B is incorrect because it is a trinomial but the leading coefficient is -5 and not 3 constant term is 3 and not -5.
Option C is correct because it is a trinomial with a leading coefficient of 3 and a constant term of -5
Option D is incorrect because it is a trinomial but the leading coefficient is 3 but constant term is 1 and not -5.
So, Option C is correct.
Keywords: Algebra
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5 is the in its value bc its on the y intercept meaning the starting point
Not sure right now give me a few mins
Answer:
A-3, B-4, C-1, D-2
Step-by-step explanation:
A:
- 5x-(3x+1)
- Expand, 5x-3x-1
- Combine like terms, 2x-1
B:
- 5x-(-3x-1)
- Expand, 5x+3x+1
- Combine like terms, 8x+1
C:
- -5x-(3x+1)
- Expand, -5x-3x-1
- Combine like terms, -8x-1
D:
- -5x-(-3x-1)
- Expand, -5x+3x+1
- Combine like terms, -2x+1
Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r = 
= 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!
