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prohojiy [21]
3 years ago
13

} } " alt=" \sqrt{ \frac{49}{81} } " align="absmiddle" class="latex-formula">
Roots of decimals ​
Mathematics
2 answers:
NNADVOKAT [17]3 years ago
7 0
7/9 and 0.7 one is points and one is a fraction
Svetradugi [14.3K]3 years ago
4 0
7/9 because 7x7=49
9x9=81
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It took Melinda 60 minutes to run 5 miles. How many miles per minute did it take Melinda?
shusha [124]
It took her 12 minutes
3 0
3 years ago
I need help with #6 please.
Juliette [100K]

9514 1404 393

Answer:

  6. (A, B, C) ≈ (112.4°, 29.5°, 38.0°)

  7. (a, b, C) ≈ (180.5, 238.5, 145°)

Step-by-step explanation:

My "work" is to make use of a triangle solver calculator. The results are attached. Triangle solvers are available for phone or tablet and on web sites. Many graphing calculators have triangle solvers built in.

__

We suppose you're to make use of the Law of Sines and the Law of Cosines, as applicable.

6. When 3 sides are given, the Law of Cosines can be used to find the angles. For example, angle A can be found from ...

  A = arccos((b² +c² -a²)/(2bc))

  A = arccos((8² +10² -15²)/(2·8·10)) = arccos(-61/160) = 112.4°

The other angles can be found by permuting the variables appropriately.

  B = arccos((225 +100 -64)/(2·15·10) = arccos(261/300) ≈ 29.5°

The third angle can be found as the supplement to the other two.

  C = 180° -112.411° -29.541° = 38.048° ≈ 38.0°

The angles (A, B, C) are about (112.4°, 29.5°, 38.0°).

__

7. When insufficient information is given for the Law of Cosines, the Law of Sines can be useful. It tells us side lengths are proportional to the sine of the opposite angle. With two angles, we can find the third, and with any side length, we can then find the other side lengths.

  C = 180° -A -B = 145°

  a = c(sin(A)/sin(C)) = 400·sin(15°)/sin(145°) ≈ 180.49

  b = c(sin(B)/sin(C)) = 400·sin(20°)/sin(145°) ≈ 238.52

The measures (a, b, C) are about (180.5, 238.5, 145°).

7 0
2 years ago
Why is it mathematically legal to multiply 2 √ 2 by √ 2 √ 2 in order to rationalize the denominator?
Gala2k [10]
Well if you're referring to rationalizing \bf \cfrac{2}{\sqrt{2}}, which simply means, getting rid of the pesky radical at the bottom

well, it boils down to, hmm say... a quantity or even a polynomial, multiplied times 1, is itself, 2*1=2, 3*1 = 3, ducks*1 = ducks, spaghetti * 1 = spaghetti

or whatever * 1 = whatever
and the value of the multiplicand, doesn't change in anyway, is the same thing before and after the multiplication by 1

now....1 can also be a fraction  \bf \cfrac{2}{2}=1\qquad \cfrac{3}{3}=1\qquad \cfrac{1,000,000}{1,000,000}=1
\\\\\\
\cfrac{ducks}{ducks}=1\qquad \cfrac{spaghetti}{spaghetti}=1\qquad \cfrac{cheese}{cheese}=1
\\\\\\
\cfrac{\textit{the quick fox jumped}}{\textit{the quick fox jumped}}=1\qquad \cfrac{whatever}{whatever}=1

so.. when you're doing \bf \cfrac{2}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\iff \cfrac{2}{\sqrt{2}}\cdot1

and the value multiplicand doesn't change in any way

now, try this in your calculator  \bf \cfrac{2}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies \cfrac{2\sqrt{2}}{\sqrt{2^2}}\implies \cfrac{2\sqrt{2}}{2}\implies \sqrt{2}\\\\
-----------------------------\\\\
\textit{check how much is }\cfrac{2}{\sqrt{2}}\textit{ in your calculator}
\\\\\\
\textit{then check how much is }\sqrt{2}\textit{ in it}
6 0
3 years ago
Transformations reflection practice
SOVA2 [1]

Answer:

The Reflection:

<em>'T</em>(-2,-2), <em>'C</em>(-2,-5), <em>'Z</em>(-5,-4), <em>'F</em>(-5,0)

5 0
2 years ago
Subtract 4x-5 from 2/5 + 7 PLEASE HELP I HAVE 4 MINUTES
Dafna11 [192]
The answer would be 4x-(62/5)

4 0
2 years ago
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