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Hunter-Best [27]
3 years ago
6

What's the GCF of 12a^2b^6, 28a^4 and 42ab^3? How did you find your answer?

Mathematics
1 answer:
8090 [49]3 years ago
6 0

12a^2b^6=(2a)(6ab^6)\\\\28a^4=(2a)(14a^3)\\\\42ab^3=(2a)(21b^3)\\\\GCF(12a^2b^6,\ 28a^4,\ 42ab^3)=2a

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Can someone pls help with this? i’ll give brainliest :)
raketka [301]

Answer:

D (I think)

Step-by-step explanation:

I used a right triangle calculator and that was the answer

Below is the process the calculator did, hope it helps.

c = \sqrt{a^{2} +b^{2}

\sqrt{12^{2} + 9^{2} } = 15

6 0
3 years ago
The first two terms in an arithmetic progression are -2 and 5. The last term in the progression is the only number in the progre
Rudik [331]

Given:

The first two terms in an arithmetic progression are -2 and 5.

The last term in the progression is the only number in the progression that is greater than 200.

To find:

The sum of all the terms in the progression.

Solution:

We have,

First term : a=-2

Common difference : d = 5 - (-2)

                                      = 5 + 2

                                      = 7

nth term of an A.P. is

a_n=a+(n-1)d

where, a is first term and d is common difference.

a_n=-2+(n-1)(7)

According to the equation, a_n>200.

-2+(n-1)(7)>200

(n-1)(7)>200+2

(n-1)(7)>202

Divide both sides by 7.

(n-1)>28.857

Add 1 on both sides.

n>29.857

So, least possible integer value is 30. It means, A.P. has 30 term.

Sum of n terms of an A.P. is

S_n=\dfrac{n}{2}[2a+(n-1)d]

Substituting n=30, a=-2 and d=7, we get

S_{30}=\dfrac{30}{2}[2(-2)+(30-1)7]

S_{30}=15[-4+(29)7]

S_{30}=15[-4+203]

S_{30}=15(199)

S_{30}=2985

Therefore, the sum of all the terms in the progression is 2985.

6 0
3 years ago
Answer the questions from the picture <br> Step by step
andre [41]

Answer:

6 = 4 mins

Step-by-step explanation:

you have to take 200 and 50 and divide them

200 divided by 50 =4 and you have to tack mins to the end of it

id_k how many class rooms for number 5

and 7 i dk how many weeks there are therefore i cant solve them

7 0
2 years ago
Which of the following equations is equivalent to log(y)= 3.994 ?
Kisachek [45]

Answer:

The correct answer is option D: y = 10^{3.994}

Step-by-step explanation:

Given:  

log(y)= 3.994

Solution:

A logarithm base b of a positive number x satisfies the following definition:

y =log_b(x) => b^y =x

For x > 0, b >0, b \neq 1

Also if no base  b  is indicated, the base of the logarithm is assumed to be  10 .

Thus, in log(y)= 3.994 base b is not indicated. so its base is assumed to be 10

now

log_{10}(y)= 3.994

Then

y = 10^{3.994}

4 0
3 years ago
Write each ratio in simplest form.<br> 1. 33/36
Anarel [89]
33 ÷ 3
----------- = 11 / 12.
36 ÷ 3

It's simplest form is 11 / 12.
7 0
3 years ago
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