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maksim [4K]
3 years ago
7

17. What are the minimum, first quartile, median, third quartile, and maximum of the data set? 40, 7, 2, 35, 12, 23, 18, 28

Mathematics
1 answer:
Rzqust [24]3 years ago
6 0
First step!  Arrange the numerals {<span>40, 7, 2, 35, 12, 23, 18, 28} in ascending order:  {2, 7, 12, 18, 23, 28, 35, 40}

Count these numerals:  there are 8 (an even number)

To find the median of this set of numerals, take the middle 2 values {18, 23} and average them:  median = (18+23)/2 = 41/2

Now, on the left of 41/2, we have the subset {2, 7 , 12, 18}.  The median of this subset is found in the same way as was 41/2 (above):
(7+12)/2 = 19/2 (First quartile)

The median of the right subset {</span>23, 28, 35, 40} is (28+35)/2, or 63/2.  This is the 3rd quartile.

The max. is 40 (this is the largest numeral given).
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CAN SOMEONE PLEASE HELP ME WITH MY GEOMETRY HOMEWORK PLEASE?
Kay [80]

Answer:

Option A

Step-by-step explanation:

The complete question is shown in the attachment.

The sum of angles in a triangle is 180 degrees.

This implies that:

m\angle A+85+53=180

m<A+138=180

m<A=180-138=42

Now we use the sine rule to find AC=b

\frac{b}{\sin 85}=\frac{85}{\sin 42}

This implies that:

b=\frac{85}{\sin 42}*\sin 85

b=126.5

5 0
3 years ago
If 7x - 4y = 23 and x + y = 8, what is the value of x?
Margaret [11]

Answer:

x=5

Step-by-step explanation:

7x - 4y = 23 and x + y = 8

Multiply the second equation by 4

4x + 4y = 32

Add this to the first equation

7x - 4y = 23

4x + 4y = 32

------------------------

11x    = 55

Divide each side by 11

11x/11 = 55/11

x = 5

8 0
3 years ago
Read 2 more answers
A bag contains yellow marbles and red marbles, 77 in total. The number of yellow marbles is 5 more than 3 times the number of re
bulgar [2K]

Answer:

41

Step-by-step explanation:

yellow marbles=5+ 3r(r is the number of red marbles)

red marbles=3r

3r+3r+5=77

6r=77-5

6r=72

r=72/6=12

yellow marbles = 5 + 3r

5+ 12 x 3

5+ 36

=41

8 0
3 years ago
The Regency Hotel has enough space at its entrance for six taxicabs to line up, wait for guests, and then load passengers. Cabs
maksim [4K]

Answer:

The appropriate solution is:

(1) 22.81 minutes

(2) 0.171

Step-by-step explanation:

According to the question, the values will be:

The service rate of guess will be:

= 5+3.5

= 8.5 \ minutes

The mean arrival rate will be:

\lambda =\frac{60}{5}

  =7.5 \ cabs/hr

The mean service rate will be:

\mu= 7.05 \ cabs/hr

(1)

The average time a cab must wait will be:

⇒ W_q=22.95-\frac{1}{7.05}

⇒       =\frac{161.798-1}{7.05}

⇒       =\frac{160.798}{7.05}

⇒       =22.81 \ minutes

(2)

The required probability will be:

⇒ P(X\geq 6)=\frac{1-2.115}{1-7.5}

⇒                  =\frac{-1.1115}{-6.5}

⇒                  =0.171

6 0
2 years ago
Given two points m and n on the coordinate plane, find the slope of line mn, and state the slope of the line perpendicular to li
ololo11 [35]
The slope of the line MN where M (9,6) and N (1,4) can be obtained by obtaining the rate of the rise over the run. This is shown below:

(y2 - y1)/(x2 - x1) = (4 - 6)/(1 - 9) = (-2)/(-8)
m1 = 1/4

The slope of the line perpendicular to line MN can be obtained by taking the negative reciprocal of the slope of line MN.

m1 = 1/4
m2 = -1/m1 = -1/(1/4) = -4

Therefore, the slope of the line perpendicular to line MN is -4.
3 0
3 years ago
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