First step! Arrange the numerals {<span>40, 7, 2, 35, 12, 23, 18, 28} in ascending order: {2, 7, 12, 18, 23, 28, 35, 40}
Count these numerals: there are 8 (an even number)
To find the median of this set of numerals, take the middle 2 values {18, 23} and average them: median = (18+23)/2 = 41/2
Now, on the left of 41/2, we have the subset {2, 7 , 12, 18}. The median of this subset is found in the same way as was 41/2 (above): (7+12)/2 = 19/2 (First quartile)
The median of the right subset {</span>23, 28, 35, 40} is (28+35)/2, or 63/2. This is the 3rd quartile.
The max. is 40 (this is the largest numeral given).
There are 4 pairs of overlapping triangles that I can see that are congruent. Two pairs share vertically opposite angles. One more pair have right angles at the bottom of the rectangle. One other pair have right angles at the top of the rectangle.