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wariber [46]
3 years ago
7

20 POINTS~ 2/5 |5x+10| -14 > -6 Please explain both answers

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
5 0

Answer:

x2

Step-by-step explanation:

We have the inequality:

\frac{2}{5}|5x+10|-14>-6

First, we can factor out a 5 from our absolute value. This yields:

\frac{2}{5}(5|x+2|)-14>-6

Simplify:

2|x+2|-14>-6

Add 14 to both sides:

2|x+2|>8

Divide both sides by 2:

|x+2|>4

Definition of Absolute Value:

x+2>4\text{ or } -(x+2)>4

Solve each case individually:

Case 1:

x+2>4

Subtract 2 from both sides:

x>2

Case 2:

-(x+2)>4

Divide both sides by -1. Flip the sign:

x+2

Subtract 2 from both sides:

x

So, our answers are:

x2

Since our inequality is a <em>greater than</em>, we will have an "or" inequality.

So, our answer is all values left to the first solution and all values to the right of the second solution:

x2

And we're done!

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Answer:

B

Step-by-step explanation:

just because :)

4 0
2 years ago
(3x^2)^-3y divided by xy
scZoUnD [109]
The number in the photo should be the answer but the problem might just be that your question was worded incorrectly.

8 0
3 years ago
A university found that of its students withdraw without completing the introductory statistics course. Assume that students reg
polet [3.4K]

Answer:

A university found that 30% of its students withdraw without completing the introductory statistics course. Assume that 20 students registered for the course.

a. Compute the probability that 2 or fewer will withdraw (to 4 decimals).

= 0.0355

b. Compute the probability that exactly 4 will withdraw (to 4 decimals).

= 0.1304

c. Compute the probability that more than 3 will withdraw (to 4 decimals).

= 0.8929

d. Compute the expected number of withdrawals.

= 6

Step-by-step explanation:

This is a binomial problem and the formula for binomial is:

P(X = x) = nCx p^{x} q^{n - x}

a) Compute the probability that 2 or fewer will withdraw

First we need to determine, given 2 students from the 20. Which is the probability of those 2 to withdraw and all others to complete the course. This is given by:

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 2) = 20C2(0.3)^2(0.7)^{18}\\P(X = 2) =190 * 0.09 * 0.001628413597\\P(X = 2) = 0.027845872524

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 1) = 20C1(0.3)^1(0.7)^{19}\\P(X = 1) =20 * 0.3 * 0.001139889518\\P(X = 1) = 0.006839337111

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 0) = 20C0(0.3)^0(0.7)^{20}\\P(X = 0) =1 * 1 * 0.000797922662\\P(X = 0) = 0.000797922662

Finally, the probability that 2 or fewer students will withdraw is

P(X = 2) + P(X = 1) + P(X = 0) \\= 0.027845872524 + 0.006839337111 + 0.000797922662\\= 0.035483132297\\= 0.0355

b) Compute the probability that exactly 4 will withdraw.

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 4) = 20C4(0.3)^4(0.7)^{16}\\P(X = 4) = 4845 * 0.0081 * 0.003323293056\\P(X = 4) = 0.130420974373\\P(X = 4) = 0.1304

c) Compute the probability that more than 3 will withdraw

First we will compute the probability that exactly 3 students withdraw, which is given by

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 3) = 20C3(0.3)^3(0.7)^{17}\\P(X = 3) = 1140 * 0.027 * 0.002326305139\\P(X = 3) = 0.071603672205\\P(X = 3) = 0.0716

Then, using a) we have that the probability that 3 or fewer students withdraw is 0.0355+0.0716=0.1071. Therefore the probability that more than 3 will withdraw is 1 - 0.1071=0.8929

d) Compute the expected number of withdrawals.

E(X) = 3/10 * 20 = 6

Expected number of withdrawals is the 30% of 20 which is 6.

5 0
3 years ago
Solve x2 = 12x – 15 by completing the square. Which is the solution set of the equation?
REY [17]
X ·2 = 12x - 15

2x = 12x - 15

2x + (-12x) = (12x - 15) + (-12x)

Result: x = 3/2

8 0
3 years ago
Read 2 more answers
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Answer:

d) All of the above

Step-by-step explanation:

A one way analysis of variance (ANOVA) test, is used to test whether there's a significant difference in the mean of 2 or more population or datasets (minimum of 3 in most cases).

In a one way ANOVA the critical value of the test will be a value obtained from the F-distribution.

In a one way ANOVA, if the null hypothesis is rejected, it may still be possible that two or more of the population means are equal.

This one way test is an omnibus test, it only let us know 2 or more group means are statistically different without being specific. Since we mah have 3 or more groups, using post hoc analysis to check, it may still be possible it may still be possible that two or more of the population means are equal.

The degrees of freedom associated with the sum of squares for treatments is equal to one less than the number of populations.

Let's say we are comparing the means of k population. The degree of freedom would be = k - 1

The correct option here is (d).

All of the above

3 0
3 years ago
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