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3 years ago

I need help!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

WINSTONCH [101]3 years ago

5 0

I can't help without a question.

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Pls help, I don’t understand how to do this

MAVERICK [17]

Answer:

5 parts are shaded and 4 parts are white so:

There are 9 parts all together.

We can then form ratio's of the white areas and the shaded areas:

White Area Ratio =

$\frac{4}{9}$

Shaded Area Ratio =

$\frac{5}{9}$

Let the area of sqaure be equated to x, which means let the entire area of the square equal to x:

x = Area of whole square

Now we can form an equation :

$\frac{5}{9} x = 165$

So now we just need to solve for x:

$x = \frac{165}{ \frac{5}{9} }$

$x = 297$

The area of the square is:

$297 {cm}^{2}$

4 0

3 years ago

Read 2 more answers

7 − x −(−5x) − 10 + 4x

patriot [66]

Answer:

8 x − 3

Hope this helps, if it does please give brainliest

3 0

3 years ago

Read 2 more answers

How do I do problem number one

jolli1 [7]

So you have to find something that multiples to six but also somehow either subtracts or adds to five. So I would pick 2 and 3 because two plus three is five. Then you would write out your equation
X2+2x+5x+6
This may not be the way your teacher taught however it is much easier for me to do it this way.

5 0

4 years ago

A ball is thrown from an initial height of 1 meter with an initial upward velocity of 15m/s. The ball's height h (in meters) aft

lakkis [162]

$\bf \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{h}=1+15t-5t^2}\implies \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{6}=1+15t-5t^2}\implies 0=-5+15t-5t^2 \\\\\\ ~~~~~~~~~~~~\textit{using the quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{5}t^2\stackrel{\stackrel{b}{\downarrow }}{-15}t\stackrel{\stackrel{c}{\downarrow }}{+5}=0 \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}$

$\bf t=\cfrac{-(-15)\pm\sqrt{(-15)^2-4(5)(5)}}{2(5)}\implies t=\cfrac{15\pm\sqrt{225-100}}{10} \\\\\\ t=\cfrac{15\pm\sqrt{125}}{10}\implies t=\cfrac{15\pm\sqrt{5^2 \cdot 5}}{10}\implies t=\cfrac{\stackrel{3}{~~\begin{matrix} 15 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\pm ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\sqrt{5}}{\underset{2}{~~\begin{matrix} 10 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}$

$\bf t=\cfrac{3\pm \sqrt{5}}{2}\implies t= \begin{cases} \frac{3+ \sqrt{5}}{2} \approx 2.618\\\\ \frac{3- \sqrt{5}}{2}\approx 0.382 \end{cases}$

8 0

3 years ago

Solve for x 6-12x = -54

kvasek [131]

Answer:

The answer of the question is 5

8 0

3 years ago