Answer:
a. t*
b. (22.87, 24.53)
c. yes
Step-by-step explanation:
We have the following data:
mean = m = 23.7
standard deviation = sd = 2.15
x = 20
Thus:
a. The critical value would be t * since the value is m <30
b. whenever the mean is less than 30, the t distribution is used, for 95% confidence interval with degree of freedom = (x - 1) df
= 20 - 1
= 19
now, for this value we look in the table of t, we find that t * = 1.729
m + - t * (sd / x ^ 81/2))
replacing
23.7 + - 1.729 * (2.15 / 20 ^ (1/2))
23.7 + - 0.8312
then the inverval would be:
23.7 + 0.8312 = 24.5312
23.7 - 0.8312 = 22.8688
(22.87, 24.53)
c. yes, the interval is accurate since the mean of 23.7 is within this value
The easiest way to do this is find all your basic info for a data set for both of the locations and cross check with the options what is true.
Number one is the answer in itself. it tells you that the first roll of the dice you got a one, a dice is numbered one through six, so if your trying to figure out the possibility that both of the dice then you would go ahead and use two over six or 2/6 which you can sum up to be 1/3. so your answer would be 1:3
I mean my best answer would be using common sense and go with 20% since there is only 80% mentioned in the question
