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3 years ago

Solve the system of equations using substitution

Mathematics

2 answers:

sergiy2304 [10]3 years ago

6 0

Answer:

Option 3 - No solution

Step-by-step explanation:

Given : The system of equations

$y=-2x+1$ and $4x+2y=-1$

To find : Solve the system of equations using substitution ?

Solution :

Let $y=-2x+1$ .....(1)

$4x+2y=-1$ ......(2)

Substitute the value of y from equation (1) in equation (2),

$4x+2(-2x+1)=-1$

$4x-4x+2=-1$

$2\neq -1$

As it is not true.

The solution of system does not exist i.e. no solution.

Therefore, option 3 is correct.

Sauron [17]3 years ago

4 0

y = −2x + 1

4x + 2y = −1

Replace Y in the second equation with the value of Y in the first one.

4x + 2(-2x +1) = -1

Distributive Property:

4x + -4x + 2 = -1

Combine like terms:

2 = -1 which is not true, so there are no solutions.

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If six people decide to come to a basketball game, but three of them are only 2/5 sure that they will stay for the entire time (

exis [7]

Answer:

the probability that at the end, at least 5 people stayed the entire time = 0.352

Step-by-step explanation:

From the question, 3 of the people are sure to stay the whole time. So, we'll deduct 3 from 6.which leaves us with 3 that are only 2/5 or 0.4 sure that they will stay the whole time.

Thus, what we need to compute to fulfill the probability that at the end, at least 5 people stayed the entire time of which we know 3 will stay, so for the remaining 3,we'll compute;

P[≥2] which is x~bin(3,0.4)

Thus;

P(≥2) = (C(3,2) x 0.4² x 0.6) + (C(3,3) x 0.4³)

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4 years ago

What is the least common multiple of 420 and 196?

maks197457 [2]

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3 years ago

Read 2 more answers

20 PTSS !!!<br> PLEASE HELPP !!

butalik [34]

Because it is extremely hard to find the area of this figure all together, it would be in our best interest to split this figure up into three different pieces: the two horizontal rectangles, and the verticle rectangle. We can find the area of all three and add them up. Be aware that there are two different ways that you can break this figure up, As shown in the attachments. I will be using the first image (the one with the tall horizontal rectangles, NOT the almost-squares).

So, we see that we have enough information to solve for the area of the left-most rectangle. Area = lw. 10 x 4 = 40, so the area is 40. Next, we have to notice, that the horizontal rectangles are also the same, so both of the areas of the two horizontal rectangles are 40.

Now, we can find the middle rectangle. We know that the length of the entire thing is 18, but it is taken up by 8 (4+4) of the horizontal triangles, so 18-8=10, so the length Is 10. We also know that the height of the horizontal rectangles is 10, so 10-3=7. Our dimensions for the rectangle are 10x7 or 70 square units. If we add them all together, 40+40+70=150.

The area is 150 square units