The solution to the problem is as follows:
<span>cos2A - cos4A = -2 sin(6A/2).sin(-2A/2) = +2 sin(3A).sinA
and
sin4A - sin2A = 2 cos(6A/2).sin(2A/2) = 2 cos(3A).sinA
Hence RHS = (cos(2A)-cos(4A))/ (sin(4A)- Sin(2A)) = sin 3A / cos 3A = tan 3A = LHS
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From the information we have the diameter of the circle is 10 cm.
Area of a circle is given by 1/4π d²
A = 1/4 π d²
π = 3.14
d² = 10² = 100
So we now calculate.
A = 1/4 × 3.14 × 100
A = 0.25 × 3.14 ×100
A = 78.5 cm²
Using radius :
The radius of this circle is 10 ÷ 2 = 5
A = π r²
A = 3.14 × 5²
A = 3.14 ×25
A = 78.5 cm²
So we still get the same answer.
I believe you would take (114*34*2)+(114*1*2)+(1*34*2) equals 8048 squared feet of wrapping paper. I could be wrong. I found the areas of each side and added them together to get a total
Answer:
The line which has slope 1/3 is a shallow line.
The line which has slope 2 is a steep line.
Both are increasing.
Step-by-step explanation:
Compare the lines by finding the slope between each pair of points.
Using the slope formula, substitute the points.
The line which has slope 1/3 is a shallow line.
The line which has slope 2 is a steep line.
