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3 years ago

Help hurry and thank u if u do

Mathematics

2 answers:

Lyrx [107]3 years ago

8 0

Answer: Jim raised %8.3

Step-by-step explanation: Well the total amount raised was $120 dollars, Jim raised $10 of that $120. Therefore jim raised %8.3 percent of the earned income.

Zarrin [17]3 years ago

3 0

50%

This is because we add up the money Jim, Jane and Bryn which was 10, 45 and 10. This equals to 65.

And half of $130 is 65 which means it is 50%

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Reese wants to organize a party and decides to save money for it.He calculates that he needs $420 in 9 weeks.He already has $60

disa [49]

Answer:

3840

Step-by-step explanation:

5 0

3 years ago

While shopping, Dawn finds a backpack that she likes on the sale rack. Its original price is $60,

Nadya [2.5K]

No. Because 33 $ is the money deducted from the 60 $. Dawn bought everything for less than 60 $.

So, if Dawn purchases everything on the rack with a 30% discount and 15% coupon the total will indeed make 45%.

We have to take 100% - 45%= 55% to know the reduction number. Let's proceed to the calculations now.

100%= 60 $

1%=60/100

55%= 60/100 × 55 = 33 $

Now NOTE; 33 $ is the money reduced from the 60 $. So, logically, 33 $ isn't the amount which Dawn purchased the whole rack. 

To find the amount at which she purchased everything, we need to do,

60 $ - 33 $ = 27 $

6 0

3 years ago

What is the answer please.... need help

mina [271]

Answer:

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

$f\left(x\right)=x^3-6x^2+3x+10$

As the highest power of the x-variable is 3 with the leading coefficients of 1.

So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

$f\left(x\right)=x^3-6x^2+3x+10$

$0=x^3-6x^2+3x+10$ ∵ $f(x)=0$

$Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

$\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

if $ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

$x=-1,\:x=2,\:x=5$

Therefore, the zeros of the function are:

$x=-1,\:x=2,\:x=5$

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.

8 0

3 years ago

What is the undefined term that mathematically uses parallel lines

dusya [7]

Answer:

point and lines

Step-by-step explanation:

8 0

3 years ago

Which graph models the equation 2x + 3y = 6?

nekit [7.7K]

: you have to solve for y. So if you do that you get y= -2/3x + 6

graph according to y=mx + b

b is y intercept, so the graph crosses the point (0, 6)

m is the slope and slope is rise over run. So go down 2 and right 3 from (0,6) as many times as you need to fill up the graph.

Then go up 2 and left 3 from (0,6) as many times as you need to fill the graph.

Put arrows at each end of your line to show that it's a line.

5 0

3 years ago