Answer:
Step-by-step explanation:
Since; the density function diagrams were not included in the question; we will be unable to determine the best which depicts this problem.
However;
Let use X to represent the time required for the delivery.
Then X~N(3.8 ,0.8)
i.e
E(x) = 3.8
s.d(x) = 0.8
NOW; P(x>4) = P(X-3.8/0.8 > 4-3.8/0.8)
= P(Z > 0.25)
= 1-P(Z < 0.25)
=1 - Φ (0.25)
= 1 - 0.5987 ( from Normal table Φ (0.25) = 0.5987 )
= 0.4013
Thus; the probability a single delivery would take more than 4 hours is 0.4013
What is the z value corresponding to the interval boundary?
The z value is calculated as:
![z = \dfrac{X- \mu}{\sigma}](https://tex.z-dn.net/?f=z%20%3D%20%5Cdfrac%7BX-%20%5Cmu%7D%7B%5Csigma%7D)
![z = \dfrac{4- 3.8}{0.8}](https://tex.z-dn.net/?f=z%20%3D%20%5Cdfrac%7B4-%203.8%7D%7B0.8%7D)
z = 0.25
Can you show picture of it
Answer:
3360 cm^2
Step-by-step explanation:
24 times 14 times 10 = 3360
Answer:
410 minutes
Step-by-step explanation:
Given that:
Time for which Jesse practices trumpet in the first week = 165 minutes
Time for which Jesse practices trumpet in the second week = 245 minutes
To find:
The total amount of time rounded to the nearest 10 minutes.
Solution:
To find the total amount of time for which Jesse practices, we need to add the time taken for practice in the first week and the time taken for practice in the second week.
Therefore, total time taken = 165 + 245 = <em>410 minutes</em>
It is already rounded off to the nearest 10 minutes.
Therefore, the answer is:
Total amount of time for which Jesse practices = 410 minutes
2, 3, 4, 6, 8, 9, 12, 18, 24, 36