Answer:
Step-by-step explanation:
Given
Represent the months with x and the earnings with y.
So:
Required
Determine the linear function
First, calculate slope (m)
The equation is then calculated using:
As a function, we have:
Urn 1 = 4 green balls and 6 blue balls, a total of 10 balls
Urn 2 = 6 green balls and 2 blue balls, a total of 8 balls.
Probability of blue balls:
Urn 1 : P = 6/10
Urn 2 : P = 2/8
Probability that both balls are blue:
6/10 * 2/8 = 6*2 / 10*8 = 12/80 = 6/40 = 3/20
Answer is B. 3/20
Answer:
A piecewise function.
Step-by-step explanation:
The problem you showed is a <em>piecewise function.</em>
In this problem, you have to plug in 3 for the value x.
However, if you take a look at the conditions that value x has, it never says that x can equal 3. <em>Thus, this function cannot be true.</em>
<em>Way to check this input is undefined: </em>
Plug in 3 for the variable x. On the first function, your output will be 4. On the second function, your output will be 8.
According to the definition of a function, a function can have many inputs but only one output. In this case, this function has one input, that is 3, but produces two outputs.
Answer:
Step-by-step explanation:
The position of an object moving horizontally after t seconds is given by the function
s = 3t - t³
a) The object is stationary when there is no external force acting on the body. When the body is at rest, the body remains in a position and here is no distance covered by the object i.e s = 0
b) velocity is the change in displacement of a body with respect to time.
v = ds/dt
S = 3t - t³
V = ds/dt = 3-3t²
at t = 2
Velocity = 3-3(2)²
Velocity = 3-12
Velocity = -9m/s
c) acceleration is the change in velocity of a body with respect to time.
acceleration = dv/dt
If v = 3-3t²
a = dv/dt = -6t
When v = 0
0 = 3-3t²
-3 = -3t²
t² = 1
t = ±√1
t = 1sec
The acceleration of the object at v = 0 occurs at t = 1sec and -1sec
a = -6(1)
a = -6m/s²
d) Given the speed of the body v modelled by the function
v = 3-3t²
The speed is decreasing when it is less than zero as shown:
3-3t²< 0
3<3t²
1<t²
±1<t
1<t and -1<t
t>±1
t >1 and t>-1
The speed is decreasing when
3-3t²<0 and t>1 or t>-1
