A hyperbola centered at the origin has a vertex at (0, 36) and a focus at (0, 39).

2 answers:

4 0

To solve this problem you must apply the proccedure shown below:
1. You have that the hyperbola has a vertex at (0,36) and a focus at (0,39).
2. Therefore, the equation of the directrices is:

a=36
a^2=1296
c=39

y=a^2/c

3. When you susbtitute the values of a^2 and c into y=a^2/c, you obtain:

y=a^2/c
 y=1296/13

4. When you simplify:

y=432/13

Therefore, the answer is: y = ±432/13

Anit [1.1K]3 years ago

4 0

Answer:

The answer is D

Step-by-step explanation:

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Pretest: Unit 8