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olganol [36]
3 years ago
13

How many grams are in 3 pounds

Mathematics
1 answer:
AnnZ [28]3 years ago
6 0
The answer is 1360.777 grams
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Find the radius of convergence, r, of the series. ? n2xn 7 · 14 · 21 · ? · (7n) n = 1
defon
I'm guessing the series is supposed to be

\displaystyle\sum_{n=1}^\infty\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}

By the ratio test, the series converges if the following limit is less than 1.

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7\cdot14\cdot21\cdot\cdots\cdot(7n)\cdot(7(n+1))}}{\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}}\right|

The first n terms in the numerator's denominator cancel with the denominator's denominator:

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7(n+1)}}{n^2x^n}\right|

|x^n| also cancels out and the remaining factor of |x| can be pulled out of the limit (as it doesn't depend on n).

\displaystyle|x|\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2}{7(n+1)}}{n^2}\right|=|x|\lim_{n\to\infty}\frac{|n+1|}{7n^2}=0

which means the series converges everywhere (independently of x), and so the radius of convergence is infinite.
3 0
3 years ago
This isn't a question, but if anyone is willing to help with scatted plots and graphs etc. could you message me about it? I am r
agasfer [191]

Answer:

yeah

Step-by-step explanation:

3 0
3 years ago
Can someone show the answer? need this quick :(
Oksanka [162]

Answer:

f(1) is 1, just look at the x-value provided in the parenthesis. f(1) means function value at x = 1, and the graph shows that at x = 1, y = 1.

8 0
3 years ago
20 Points please help!!<br><br> Solve each equation below, show your work! <br><br> x^3 = -125
Greeley [361]
X^3 = (-5)^3
the answer is x=5
5 0
3 years ago
Read 2 more answers
Jimmy was supposed to multiply a certain number by 43 but by mistake he multiplied that number by 34 as a result his answer was
vredina [299]

Answer:

345

Step-by-step explanation:

We can solve this problem by two equations. Our variables will be the following:

x is the amount to be multiplied

and y is the amount that should be obtained by multiplying by 43

Thus our <u>first equation</u> is:

43x=y

But the problem tells us that there was an error and the number x was multiplied by 34, so the result failed by 3105, thus the <u>second equation</u> is as follows:

34x=y-3105

By multiplying the quantity by 34, an amount is obtained that differs from 3105 from what it would have been obtained if multiplied by 43.

Now we are going to <u>replace the first equation in the second one </u>(y=43x):

34x=43x-3105

And clear to find x:

3105=43x-34x\\3105=9x\\\frac{3105}{9}=x\\345=x

The number that jimmy was supposed to multiply by 43 is 345.

6 0
3 years ago
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