To solve this problem it is necessary to apply the concepts related to the kinematic equations of movement description.
From the definition we know that the speed of a body can be described as a function of gravity and height
Then applying the kinematic equation of displacement, the height can be written as
Re-arrange to find t,
Thus the calculation of the displacement would be subject to
Therefore the required distance must be 0.547m
Answer:
8090.01 J
Explanation:
The formula for kinetic energy is 
. We are given the mass and velocity, so plug what is given into the equation. 
Answer:
191.316 K or -81.684 °C
Explanation:
From general gas law,
P₁V₁/T₁ = P₂V₂/T₂ ................ Equation 1
Where P₁ = Initial pressure, V₁ = Initial volume, T₁ = Initial temperature, P₂ = Final pressure, V₂ = Final volume, T₂ = Final Temperature.
Make T₂ the subject of the equation.
T₂ = P₂V₂T₁/P₁ V₁ ............... Equation 2
Given: P₁ = 5.00×10⁶ Pa, T₁ = 25.0°C = 298 K, P₂ = 1.07×10⁶.
Let: V₁ = y cm³, V₂ = 3y cm³
Substitute into equation 2,
T₂ = (1.07×10⁶×298×3y)/(5.00×10⁶×y)
T₂ =191.316 K.
Hence the final temperature = 191.316 K or -81.684 °C
Answer:
Statement 1 and statement 2 are correct and statement 2 is the correct explanation of statement 1
Explanation:
Both the velocity and kinetic energy of a gas molecule depends on its relative molecular mass according to Graham's law of diffusion in gases. Hence, the greater the relative molecular mass of the gas, the lesser its average velocity and kinetic energy.
Hence we can see that statement 2 vividly explains the postulation of statement 1 and makes the points more easily comprehensible.
Since isotopes of any given element all contain the same number of protons,
