Ask question

Ask question

All categories

3 years ago

11

Two forces, F1 and F2, act at a point. F1 has a magnitude of 8.60 N and is directed at an angle of 55.0 ∘ above the negative x a

xis in the second quadrant. F2 has a magnitude of 7.00 N and is directed at an angle of 53.2 ∘ below the negative x axis in the third quadrant. What is the x component Fx of the resultant force?

1 answer:

9966 [12]3 years ago

5 0

Answer:9.125 N

Explanation:

Given

Magnitude of Force $F_1=8.60 N$ at angle of $55^{\circ}$ above negative x axis

Magnitude of Force $F_2=7 N$ at angle of $53.2^{\circ}$ below negative x axis

$\theta _1=180^{\circ}-55^{\circ}=125^{\circ}$

$\theta _2=180^{\circ}+53.2^{\circ}=233.2^{\circ}$

Thus net force in x direction

$F_x=F_1\cos \theta _1+F_2\cos \theta _2$

$F_x=8.6\times \cos (125)+7\times \cos (233.2)$

$F_x=-9.1251 N$ towards negative x axis

You might be interested in

A child throws a ball vertically upward to a friend on a balcony 28 m above him. The friend misses the ball on its upward flight

photoshop1234 [79]

Answer:

$t=1.9 sec$

Explanation:

From the question we are told that:

Height $h=28m$

Time $t=3s$

Generally the Newton's equation for Initial velocity upward is mathematically given by

$s=ut+\frtac{1}{2}at^2$

$28=3u-\frac{1}{2}*9.8*3^2$

$u=24.03m/s$

Generally the velocity at elevation and depression occurs as ball arrives and passes through S=28

$v=\sqrt{24.03-2*9.8*28}$

$v=5.35m/s and -5.35m/s$

Generally the Newton's equation for time to reach initial velocity is mathematically given by

$v=u+at$

$5.35=24.03-9.8t$

$t=\frac{28.03-5.35}{9.8}$

$t=1.9 sec$

4 0

2 years ago

The circuits, P and Q, show two different ammeter-voltmeter methods of measuring resistance. Suppose the ammeter has a resistanc

qaws [65]

Answer:

Uncorrected values for

For circuit P

R = 2.4 ohm

For circuit Q

R = 2.4 ohm

Corrected values

for circuit P

R = 12 OHM

For circuit Q

R = 2.3 ohm

Explanation:

Given data:

Ammeter resistance 0.10 ohms

Resister resistance 3.0 ohms

Voltmeter read 6 volts

ammeter reads 2.5 amp

UNCORRECTED VALUES FOR

1) circuit P

we know that IR =V

$R = \frac{6}{2.5} - 2.4 ohm$

2) circuit Q

R = 2.4 ohm as no potential drop across ammeter

CORRECTED VALUES FOR

1) circuit p

IR = V

$\frac{3R}{R+3} \times 2.5 = 6$

R= 12 ohm

2) circuit Q

$I\times (R+0.1) =V$

$R+0.1 =\frac{6}{2.5}$

R = 2.3 ohm

5 0

3 years ago

Help me with physics.....<br>due right now

serious [3.7K]

In any case, your mass would be<em> 68 kg </em>no matter what

3 0

2 years ago

Travels 11,000 feet along a dark desert highway if the car averages 84 mph find the amount of time to cover this distance

laila [671]

The time taken by traveler to cover the distance is,

$t=\frac{d}{v}$

Substitute the known values,

$\begin{gathered} t=\frac{(11000\text{ ft)}}{(84\text{ mph)(}\frac{1.46667\text{ ft/s}}{1\text{ mph}})_{}} \\ \approx89.3\text{ s} \end{gathered}$

Therefore, the time taken by traveler to cover the distance is 89.3 s.

5 0

1 year ago

If the forces acting on an object are balanced, wihat must be true about the motion of this object?

wolverine [178]

The correct answer to the question is : D) Be moving at a constant velocity.

EXPLANATION:

As per Newton's first laws of motion, every body continues to be at state of rest or of uniform motion in a straight line unless and until it is compelled by some external unbalanced forces acting on it.

Hence, it is the unbalanced force which changes the state of rest or motion of a body. Balanced force is responsible for keeping the body to be either in static equilibrium or in dynamic equilibrium.

As per the options given in the question, the last one is true for an object under balanced forces.

5 0

3 years ago