Question

Two forces, F1 and F2, act at a point. F1 has a magnitude of 8.60 N and is directed at an angle of 55.0 ∘ above the negative x axis in the second quadrant. F2 has a magnitude of 7.00 N and is directed at an angle of 53.2 ∘ below the negative x axis in the third quadrant. What is the x component Fx of the resultant force?

Answer 1

Answer:9.125 N

Explanation:

Given

Magnitude of Force $F_1=8.60 N$ at  angle of $55^{\circ}$ above negative x axis

Magnitude of  Force $F_2=7 N$ at  angle of $53.2^{\circ}$ below negative x axis

$\theta _1=180^{\circ}-55^{\circ}=125^{\circ}$

$\theta _2=180^{\circ}+53.2^{\circ}=233.2^{\circ}$

Thus net force in x direction

$F_x=F_1\cos \theta _1+F_2\cos \theta _2$

$F_x=8.6\times \cos (125)+7\times \cos (233.2)$

$F_x=-9.1251 N$ towards negative x axis