<h3><u>Answer;</u></h3>
3p34s23d7
<h3><u>Explanation</u>;</h3>
- Electrons in an atom are contained in specific energy levels that are different distances from the nucleus.
- Within each energy level is a volume of space where specific electrons are likely to be located, called orbitals. Orbitals are of different shapes, denoted by a letter (s, p, d, f, g).
- S-orbital takes a maximum of two electrons, p-orbital take a maximum of six electrons, d-orbital takes a maximum of 10 electrons, and so fourth.
- The electron filling pattern takes; 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p.........
- Therefore; in this case after 3p3, we then go to 4s, with 2 electrons, then 3d which takes 7 electrons.
6NaC₂H₃O₂ + Fe₂O₃ → 2Fe(C₂H₃O₂)₃ + 3Na₂O
Explanation:
Given equation;
NaC₂H₃O₂ + Fe₂O₃ → Fe(C₂H₃O₂)₃ + Na₂O
To find the coefficient that will balance this we equation, let us set up simple mathematical algebraic expressions that we can readily solve.
Let us have at the back of our mind that, in every chemical reaction, the number of atom is usually conserved.
aNaC₂H₃O₂ + bFe₂O₃ → cFe(C₂H₃O₂)₃ + dNa₂O
a, b, c and d are the coefficients that will balance the equation.
conserving Na; a = 2d
C: 2a = 6c
H: 3a = 9c
O; 2a + 3b = 6c + d
Fe: 2b = c
let a = 1
solving:
2a = 6c
2(1) = 6c
c = 
2b = c
b =
= 
d = 2a + 3b - 6c = 2(1 ) + (3 x
) - (6 x
) = 
Now multiply through by 6
a = 6, b = 1, c = 2 and d = 3
6NaC₂H₃O₂ + Fe₂O₃ → 2Fe(C₂H₃O₂)₃ + 3Na₂O
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Balanced equation brainly.com/question/9325293
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Answer:
mole fraction of N_2 O = 0.330
mole of fraction SF_4 = 0.669
PRESSURE OF N_2 O = 39127.053 Pa
pressure of SF_4 = 792126.36
Total pressure = 118253.413 Pa
Explanation:
Given data:
volume of tank 8 L
Weight of dinitrogen difluoride gas 5.53 g
weight of sulphur hexafluoride gas 17.3 g
Amount of 
amount of 
mole fraction of 
mole of fraction
PV = nRT
P of N_2 O 
mole of SF_4
Total pressure = 39127.053 + 79126.36 = 118253.413 Pa
The easiest answer and most relevant is because it didn't sink
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Shale actually forms in the part of the rock cycle called compaction.