Answer:
The cost would be $1.68
Explanation:
I found the answer by multiplying
.67x or .67lb with 2.5, getting $1.68
The mass of carbon in 1 liter of mixture = 1.108 g
<h3>What is the mass of carbon in 1 liter of the mixture?</h3>
The mass of carbon in 1 liter of the mixture is determined as follows:
First the moles of gas is determined using the ideal gas formula:
n = (1 * 1)/(0.08205L * 298)
n = 0.0409 mole of total gas
mass of gas is then determined using the formula:
mass = 1 * 1.375
mass = 1.375 g
Let x = mass of CH₄ and y = mass of C₄H₁₀
x + y = 1.375 g
nCH₄ + nC₄H₁₀ = ntotat
moles = mass/molar mass
x + y = 1.695 => y = 1.695 - x
(x/molar mass of CH₄) + [(1.375 - x)/ molar mass C₄H₁₀ = 0.0409
x/16 + (1.375 - x)/58 = 0.0409
x = 0.380 g CH₄
y = 1.375 - 0.380
y = 0.995 g of C₄H₁₀
mass of C in CH₄ = 12/16 * 0.380 = 0.285
mass of C in C₄H₁₀ = 48/58 * 0.995 = 0.823
Mass of carbon in 1 liter of mixture = 0.285 + 0.823
Mass of carbon in 1 liter of mixture = 1.108 g
In conclusion, the carbon is the major component in the mixture.
Learn more about ideal gas at: brainly.com/question/20348074
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The climate would become colder...
1) Balanced chemical equation
H2SO4 + 2NaOH ---> Na2 SO4 + 2H2O
=> 1 mol H2SO4 : 2 moles NaOH
2) Convert 89.3 g of H2SO4 and 96.0 g of NaOH to moles
Molar mass of H2SO4 = 98.1 g/mol
Molar mass of NaOH = 40.0 g/mol
moles = mass in grams / molar mass
moles H2SO4 = 89.3 g / 98.1 g/mol = 0.910 mol
moles NaOH = 96.0 g / 40.0 g/mol = 2.40 mol
3) Theoretical molar ratio = 2 moles NaOH / 1 mol H2SO4
So, all the 0.91 mol of H2SO4 will be consumed along with 1.820 (2*0.91) moles of NaOH, and 0.580 moles (2.40 - 1.82) of NaOH will be left over by the chemical reaction.
4) Convert 0.580 moles NaOH to mass
0.580 moles * 40.0 g/mol = 23.2 g of NaOH will be left over
Did you mean moles? Instead of miles
If so it’s 0. 330568289543697
