Identify NaOH (aq) + HNO3(aq) → NaNO3(aq) + H2O(1)
1 answer:
You might be interested in
Answer:
(a)
(b)
Explanation:
Hello,
In this case, since the both gases behave ideally, with the given information we can compute the moles of He in A:
Thus, since the final pressure is 3.60 bar, we can write:
The moles of helium could be computed via solver as:
Or algebraically:
In such a way, the volume of the compartment B is:
Finally, he mole fraction of He is:
Regards.
Above question is incomplete. Complete question is attached below
........................................................................................................................
Solution:
Reduction potential of metal ions are provided below. Higher the value to reduction potential, greater is the tendency of metal to remain in reduced state.
In present case, reduction potential of Au is maximum, hence it is least prone to undergo oxidation. Hence, it is least reactive.
On other hand, reduction potential of Na is minimum, hence it is most prone to undergo oxidation. Hence, it is most reactive.
........................................................................................................................
Solution:
Reduction potential of metal ions are provided below. Higher the value to reduction potential, greater is the tendency of metal to remain in reduced state.
In present case, reduction potential of Au is maximum, hence it is least prone to undergo oxidation. Hence, it is least reactive.
On other hand, reduction potential of Na is minimum, hence it is most prone to undergo oxidation. Hence, it is most reactive.