Read the following summary of the article

Chemistry

1 answer:

True [87]2 years ago

6 0

Answer:

Explanation:

zxds

You might be interested in

Gold has a density of 1,200 lb./ft. What is the density of gold in g/em? For conversion factors use I lb. 453.6 g, and l inch-2.

Jlenok [28]

Answer: The density of gold in $g/cm^3$ is $19.22g/cm^3$

Explanation:

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

$\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}$

We are given:

Density of gold = $1200lb/ft^3$

Using conversion factors:

1 lb = 453.6 g

1 feet = 12 inches

1 inch = 2.54 cm

Converting given quantity into $g/cm^3$ , we get:

$\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3$

Hence, the density of gold in $g/cm^3$ is $19.22g/cm^3$

6 0

3 years ago

Help! Please :) Thank you

BartSMP [9]

First one??

I believe this is the correct answer

5 0

2 years ago

A:1 B:2 C:3 D:4 HELPPPPPP

Naya [18.7K]

The answer is 4 hope that help.

6 0

2 years ago

Read 2 more answers

Methanol can be synthesized by combining carbon monoxide and hydrogen. CO(g) 2H2(g) CH3OH(g) . A reaction vessel contains the th

mihalych1998 [28]

Answer:

The answer is C. The partial pressure of hydrogen will be unchanged.

Explanation:

$CO_{(g)} + 2H_{2(g)}$ ⇒ $CH_{3}OH$

Argon with electronic configuration $1s^{2}$ $2s^{2}$ $2p^{6}$ $3s^{2}$ $3p^{6}$ (that is atomic number 18) is an inert gas making it unreactive and it's addition to the reaction has no effect on the partial pressure of either the reactant or production or the state of the system.