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Alik [6]
3 years ago
5

What's time 21/2 hours after 11:45 AM?

Mathematics
1 answer:
Snezhnost [94]3 years ago
7 0
2 and 1/2 hours is 2 hours and 30 minutes
So
1145+230=13:75 (3:15 is your answer)

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3.1.10
TiliK225 [7]
The answer is C. (True) did some research and that’s what all my sources say ;)
5 0
3 years ago
If there's a 9% tax, and the couch is $227.49 what will the total be?
ZanzabumX [31]

Answer

Step-by-step explanation:

227.49 x 1.09 = 247.96

4 0
3 years ago
Read 2 more answers
Please answer correctly !!!!!!! Will mark Brianliest !!!!!!!!!!!
icang [17]

Answer:

x=-2\\x=2

(You only need to give one solution)

Step-by-step explanation:

We have the following equation

(x^2+1)^2-5x^2-5=0

First, we need to foil out the parenthesis

x^4+2x^2+1-5x^2-5=0

Now we can combine the like terms

x^4-3x^2-4=0

Now, we need to factor this equation.

To factor this, we need to find a set of numbers that add together to get -3 and multiply to give us -4.

The pair of numbers that would do this would be 1 and -4.

This means that our factored form would be

(x^2-4)(x^2+1)=0

As the first binomial is a difference of squares, it can be factored futher into

(x^2+1)(x+2)(x-2)=0

Now, we can get our solutions.

The first binomial will produce two complex (Not real) solutions.

x+2=0\\\\x=-2

x-2=0\\\\x=2

So our solutions to this equation are

x=-2\\x=2

3 0
3 years ago
Write an equation that expresses the relationship. Then solve the equation for B.
Serhud [2]

Answer:

kkkkkkkllllll

Step-by-step explanation:

llllllllllllllllllllllllll

8 0
3 years ago
Given cosα = −3/5, 180 < α < 270, and sinβ = 12/13, 90 < β < 180
torisob [31]

I got

-  \frac{6 3}{65}

What we know

cos a=-3/5.

sin b=12/13

Angle A interval are between 180 and 270 or third quadrant

Angle B quadrant is between 90 and 180 or second quadrant.

What we need to find

Cos(b)

Cos(a)

What we are going to apply

Sum and Difference Formulas

Basics Sine and Cosines Identies.

1. Let write out the cos(a-b) formula.

\cos(a - b)  =  \cos(a)  \cos(b)  +  \sin(a)  \sin(b)

2. Use the interval it gave us.

According to the given, Angle B must between in second quadrant.

Since sin is opposite/hypotenuse and we are given a sin b=12/13. We. are going to set up an equation using the pythagorean theorem.

.

{12}^{2}  +  {y}^{2}  =  {13}^{2}

144 +  {y}^{2}  = 169

25 =  {y}^{2}

y = 5

so our adjacent side is 5.

Cosine is adjacent/hypotenuse so our cos b=5/13.

Using the interval it gave us, Angle a must be in the third quadrant. Since cos is adjacent/hypotenuse and we are given cos a=-3/5. We are going to set up an equation using pythagorean theorem,

.

( - 3) {}^{2}  +  {x}^{2}  =  {5}^{2}

9 +  {x}^{2}  = 25

{x}^{2}  = 16

x = 4

so our opposite side is 4. sin =Opposite/Hypotenuse so our sin a =4/5.Sin is negative in the third quadrant so

sin a =-4/5.

Now use cosine difference formula

-  \frac{3}{5}  \times  \frac{5}{13}  +   - \frac {4}{5}  \times  \frac{12}{13}

- \frac{15}{65} + (  - \frac{48}{65}  )

-  \frac{63}{65}

Hope this helps

6 0
3 years ago
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