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valentina_108 [34]
3 years ago
6

Jawad has seven rocks ​

Mathematics
2 answers:
Neporo4naja [7]3 years ago
8 0

Answer:

What’s the question?

Step-by-step explanation:

Alenkasestr [34]3 years ago
7 0
What’s the question?
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What is the value of x for part A and part B
GuDViN [60]
Part A :

So the two sides are equivalent,

9x - 18 = 3x

Solve for x and get 3.

~~

Answer : x = 3

~~

Part B :

To find JM, simply substitute x for 3 and solve,

9(3) - 18
27 - 18 = 9
~^

Answer : JM = 9

~~

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey

5 0
3 years ago
Three dump trucks are carrying topsoil to a construction site. Truck A carries 3,545 lb, Truck 8 carries 1,758 lb, and Truck C c
VikaD [51]
The total weight being carried is
   3545 +1758 +3697 = 9000 . . . . . pounds

Each ton is 2000 pounds, so together the trucks are carrying
   (9000 lb) × (1 t)/(2000 lb) = 4.5 t

Altogether, the 3 trucks are carrying 4.5 tons of topsoil.
8 0
3 years ago
Read 2 more answers
A coin will be tossed three times, and each toss will be recorded as heads (H) or tails (T). Give the sample space describing al
cricket20 [7]

Answer:

Sample space:

{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

Third toss is heads:

{HHT, HTT, THT, TTT}

First toss is heads, second tails and third heads:

{HTH}

Explanation:

In order to find the sample space we need to write all the possible outcomes from tossing the coin three times.You can start by writting all the possible outcomes for the first toss being a head and finish with all the possible outcomes for the first toss being Tails. The number of elements in the sample space can be found by multiplying the possible outcomes of each toss together, so 2*2*2=8

{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

For the third toss being heads we will have one restriction this time. Which is that the third toss is Tails. You can take the elements from the sample space where the third element is a tails. In this case, the number of elements can be calculated by multiplying the possible outcomes for only the first two tosses 2*2=4

{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

For first toss is heads, second tails and third heads there is only one possible way for you to get this outcome so there is only one element to this set.

{HTH}

4 0
3 years ago
If f and g are differentiable functions for all real values of x such that f(1) = 4, g(1) = 3, f '(3) = −5, f '(1) = −4, g '(1)
belka [17]

Answer:

h'(1)=0

Step-by-step explanation:

We use the definition of the derivative of a quotient:

If h(x)=\frac{f(x)}{g(x)}, then:

h'(x)=\frac{f'(x)*g(x)-f(x)*g'(x)}{(g(x))^2}

Since in our case we want the derivative of h(x) at the point x = 1, which is indicated by: h'(1), we need to evaluate the previous expression at x = 1, that is:

h'(1)=\frac{f'(1)*g(1)-f(1)*g'(1)}{(g(1))^2}

which, by replacing with the given numerical values:

f(1) =4\\g(1)=3\\f'(1)=-4\\g'(1)=-3

becomes:

h'(1)=\frac{f'(1)*g(1)-f(1)*g'(1)}{(g(1))^2}=\\=\frac{-4*3-4*(-3)}{(3)^2}=\frac{-12+12}{9} =\frac{0}{9} =0

3 0
3 years ago
Given the following data set 2,3,1,6,1,1,1,0,2,4,5,1,2,2,3<br>Mean <br>Median <br>Range<br>Mid range
igomit [66]

Answer:

mean: 34/15=2.27

median: 2

range: highest-lowest...... 6-0=6

mid range: high + low divided by 2

6+0=6/2=3

8 0
3 years ago
Read 2 more answers
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