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eduard
4 years ago
9

Two identical spheres carry charges of +0.6 coulomb and -0.2 coulomb, respectively. If these spheres touch, the resulting charge

on the first sphere will be
1. +0.8 C 2. +0.2 C 3. -0.3 C 4. +0.4 C
Physics
1 answer:
masya89 [10]4 years ago
5 0

Answer:

2. +0.2 C

Explanation:

When the two spheres touch, the total charge will be redistributed such that the two spheres are at same potential:

V_1 = V_2

The potential can be rewritten as ratio between the charge on the sphere (Q) and the capacitance of the sphere (C):

\frac{Q_1}{C_1}=\frac{Q_2}{C_2}

Since the two spheres are identical, they have same capacitance:

C_1 =C_2=C

So we can write

\frac{Q_1}{C}=\frac{Q_2}{C}

Q_1=Q_2

And since the total charge is

Q=+0.6 C-0.2 C=+0.4 C

And this charge will be redistributed equally on the two spheres (Q_1 = Q_2), we have

Q_1 = Q_2 = \frac{Q}{2}=\frac{+0.4 C}{2}=+0.2 C

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