Question

The strings in a compound bow behave approximately like a

Answer 1

The speed at which the arrow would be launched is 133.42 m/s

The work-energy theorem asserts that the net work done applied by the forces on a particular object is equivalent to the change in its kinetic energy.

The equation for the work-energy theorem can be computed as:

$\mathbf{W =\Delta K.E}$

$\mathbf{F\Delta x =\dfrac{1}{2} mv^2}$

where;

• Force (F) = 267 N
• distance Δx = 0.60 m
• mass (m) = 18 g
• speed (v) = ???

From the above equation, let make speed(v) the subject of the formula:

∴

$\mathbf{v = \sqrt{\dfrac{2(F \Delta x)}{m}} }$

$\mathbf{v = \sqrt{\dfrac{2(267 \times 0.60)}{0.018}} }$

v = 133.42 m/s

Learn more about the work-energy theorem here:

brainly.com/question/17081653